A = (2^10.2^13-2^21.20)/2^24 B = (1+ 1/1.3 )(1+ 1/2.4 )…(1+ 1/2016.2018 )

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1. Đáp án:

    

   Giải thích các bước giải:

   B = (1+ 1/1.3 )(1+ 1/2.4 )…(1+ 1/2016.2018 )

   $= (1.3+1. \frac{1}{3})….(\frac{2016.2018+ 1}{2016.2018})$

   $= (2. 2. \frac{1}{3})…(\frac{2017. 2017}{2016. 2018})$

   $= (2…2017).(\frac{2…..2017}{(1.2….2016).(3…2018)}$

   $= \frac{2017.2}{2018}$

   $= \frac{2017. 2}{1006. 2}$

   $= \frac{2017}{1006}$

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