a, 2 – | x + 3 | = 1 b, 3 × | x – 4 | – 2 = 4 05/12/2021 Bởi Amaya a, 2 – | x + 3 | = 1 b, 3 × | x – 4 | – 2 = 4
`a)2-|x-3|=1` `→|x-3|=2-1` `→|x-3|=1` `→` \(\left[ \begin{array}{l}x-3=1\\x-2=-1\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=4\\x=1\end{array} \right.\) Vậy `x∈{4;1}` `b)3×|x-4|-2=4` `→3×|x-4|=6` `→|x-4|=2` `→` \(\left[ \begin{array}{l}x-4=2\\x-4=-2\end{array} \right.\) `→` \(\left[ \begin{array}{l}x=6\\x=2\end{array} \right.\) Vậy `x∈{6;2}` Bình luận
Sợ sai lém : Bài làm : a , 2 – | x + 3 | = 1 | x + 3 | = 2 – 1 | x + 3 | = 1 x + 3 = 1 hoặc x + 3 = -1 +) x + 2 = 1 +) x + 2 = -1 x = 1 – 2 x = -1 – 2 x = – 1 x = -3 b, mik chịu Bình luận
`a)2-|x-3|=1`
`→|x-3|=2-1`
`→|x-3|=1`
`→` \(\left[ \begin{array}{l}x-3=1\\x-2=-1\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=4\\x=1\end{array} \right.\)
Vậy `x∈{4;1}`
`b)3×|x-4|-2=4`
`→3×|x-4|=6`
`→|x-4|=2`
`→` \(\left[ \begin{array}{l}x-4=2\\x-4=-2\end{array} \right.\)
`→` \(\left[ \begin{array}{l}x=6\\x=2\end{array} \right.\)
Vậy `x∈{6;2}`
Sợ sai lém :
Bài làm :
a , 2 – | x + 3 | = 1
| x + 3 | = 2 – 1
| x + 3 | = 1
x + 3 = 1 hoặc x + 3 = -1
+) x + 2 = 1 +) x + 2 = -1
x = 1 – 2 x = -1 – 2
x = – 1 x = -3
b, mik chịu