a) x^2-3x+2=0 b) (4x-10)(24+5x)=0 chậm thì chịu =-= 03/08/2021 Bởi Maria a) x^2-3x+2=0 b) (4x-10)(24+5x)=0 chậm thì chịu =-=
a)`x^2-3x+2=0` `<=>(x-2)(x-1) = 0` `<=>`$\left[ \begin{array}{l}x-2=0\\x-1=0\end{array} \right.$ `<=>`$\left[ \begin{array}{l}x=2\\x=1\end{array} \right.$ Vậy: `S={2;1}` b)`(4x-10)(24+5x)=0` `<=>`$\left[ \begin{array}{l}4x-10=0\\24+5x=0\end{array} \right.$ `<=>`$\left[ \begin{array}{l}4x=10\\5x=-24\end{array} \right.$ `<=>`$\left[ \begin{array}{l}x=\frac{5}{2}\\x=-\frac{24}{5}\end{array} \right.$ Vậy: `S={5/2;-24/5}` :VVVVVVVVVVVVVVVVVVVVVVV Bình luận
a)`x^2-3x+2=0`
`<=>(x-2)(x-1) = 0`
`<=>`$\left[ \begin{array}{l}x-2=0\\x-1=0\end{array} \right.$
`<=>`$\left[ \begin{array}{l}x=2\\x=1\end{array} \right.$
Vậy: `S={2;1}`
b)`(4x-10)(24+5x)=0`
`<=>`$\left[ \begin{array}{l}4x-10=0\\24+5x=0\end{array} \right.$
`<=>`$\left[ \begin{array}{l}4x=10\\5x=-24\end{array} \right.$
`<=>`$\left[ \begin{array}{l}x=\frac{5}{2}\\x=-\frac{24}{5}\end{array} \right.$
Vậy: `S={5/2;-24/5}`
:VVVVVVVVVVVVVVVVVVVVVVV
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