a.3+|2x-1|=2 b.11-(15+11-2x)=x-(25-9) c.-3x-12=(-9)-(-15+2x) d.2-x=15-(-5+2x) 22/10/2021 Bởi Jade a.3+|2x-1|=2 b.11-(15+11-2x)=x-(25-9) c.-3x-12=(-9)-(-15+2x) d.2-x=15-(-5+2x)
a. `3 + |2x – 1 |` `=` `2` `⇔` `| 2x – 1 | = -1` `⇔` `x=⦰` b. `11 – ( 15 + 11 – 2x) = x – ( 25 – 9 )` `⇔` `11 – (15 + 11 – 2x) = x-16` `⇔` `11 – (26 – 2x) = x – 16` `⇔` `11-26+2x` `=` `x-16` `⇔` `-15+2x` `=` `x-16` `⇔` `-15+16` `=` `x-2x` `⇔` `1` `=` `-x` `⇔` `x` `=` `-1` c. `-3x-12 = (-9)-(-15+2x)` `⇔` `-3x-12 = (-9)+15-2x` `⇔` `-3x-12 = 6-2x` `⇔` `-3x+2x = 6+12` `⇔` `x = 18` d. `2 – x = 15 – (-5 + 2x)` `⇔` `2-x = 15-5-2x` `⇔` `2-x = 10-2x` `⇔` `2-10 = x-2x` `⇔` `-8 = x` `⇔` `x = -8` Bình luận
a. `3 + |2x – 1 |` `=` `2`
`⇔` `| 2x – 1 | = -1`
`⇔` `x=⦰`
b. `11 – ( 15 + 11 – 2x) = x – ( 25 – 9 )`
`⇔` `11 – (15 + 11 – 2x) = x-16`
`⇔` `11 – (26 – 2x) = x – 16`
`⇔` `11-26+2x` `=` `x-16`
`⇔` `-15+2x` `=` `x-16`
`⇔` `-15+16` `=` `x-2x`
`⇔` `1` `=` `-x`
`⇔` `x` `=` `-1`
c. `-3x-12 = (-9)-(-15+2x)`
`⇔` `-3x-12 = (-9)+15-2x`
`⇔` `-3x-12 = 6-2x`
`⇔` `-3x+2x = 6+12`
`⇔` `x = 18`
d. `2 – x = 15 – (-5 + 2x)`
`⇔` `2-x = 15-5-2x`
`⇔` `2-x = 10-2x`
`⇔` `2-10 = x-2x`
`⇔` `-8 = x`
`⇔` `x = -8`