a) 3+2/3 b) 4- 8/5 + 2/10 c) 1/5 : 1/3 : 7/5

a) 3+2/3
b) 4- 8/5 + 2/10
c) 1/5 : 1/3 : 7/5

0 bình luận về “a) 3+2/3 b) 4- 8/5 + 2/10 c) 1/5 : 1/3 : 7/5”

  1. @gaukind2008

    a) 3 + $\frac{2}{3}$

        =$\frac{3}{1}$ + $\frac{2}{3}$ 

        = $\frac{9}{3}$ + $\frac{2}{3}$

        = $\frac{11}{3}$

    b) 4 – $\frac{8}{5}$ + $\frac{2}{10}$

        = 4 – $\frac{8}{5}$ + $\frac{1}{5}$

        = 4 – ( $\frac{8}{5}$ + $\frac{1}{5}$ )

        = 4- $\frac{7}{5}$

        = $\frac{20}{5}$ – $\frac{7}{5}$

        = $\frac{13}{5}$

    c) $\frac{1}{5}$ ÷ $\frac{1}{3}$ ÷$\frac{7}{5}$

        = $\frac{1}{5}$ × $\frac{3}{1}$ ÷ $\frac{5}{7}$

        = $\frac{3}{5}$ ÷ $\frac{7}{5}$

        = $\frac{3}{5}$ × $\frac{5}{7}$ 

        = $\frac{3}{7}$

    #Team FA

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  2. `text{Giải thích các bước giải:}`

    $\rm a)\\3+\dfrac{2}{3}\\=\dfrac{9}{3}+\dfrac{2}{3}\\=\dfrac{9+2}{3}\\=\dfrac{11}{3}\\b)\\4-\dfrac{8}{5}+\dfrac{2}{10}\\=4-\dfrac{8}{5}+\dfrac{1}{5}\\=4-\left(\dfrac{8}{5}-\dfrac{1}{5}\right)\\=4-\dfrac{7}{5}\\=\dfrac{20}{5}-\dfrac{7}{5}\\=\dfrac{20-7}{5}\\=\dfrac{13}{5}\\c)\\\dfrac{1}{5}:\dfrac{1}{3}:\dfrac{7}{5}\\=\dfrac{1}{5}.\dfrac{3}{1}:\dfrac{7}{5}\\=\dfrac{3}{5}:\dfrac{7}{5}\\=\dfrac{3}{5}.\dfrac{5}{7}\\=\dfrac{3}{7}$

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