A(x)=(3x + 3x^2 + 2x^3 + 2x^4 – 7x+5)+(2x^2-3x+3x^5 + 2x^4 +7) B(x)=(3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x+5)-(2x^2-3x+3x^5 + 2x^4 +7)

0 bình luận về “A(x)=(3x + 3x^2 + 2x^3 + 2x^4 – 7x+5)+(2x^2-3x+3x^5 + 2x^4 +7) B(x)=(3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x+5)-(2x^2-3x+3x^5 + 2x^4 +7)”

1. *Lời giải :

   $A (x) = (3x + 3x^2 + 2x^3 + 2x^4 – 7x + 5) + (2x^2 – 3x + 3x^5 + 2x^4 + 7)\\⇔ A (x) = 3x + 3x^2 + 2x^3 + 2x^4 – 7x + 5 + 2x^2 – 3x + 3x^5 + 2x^4 + 7\\⇔ A (x) = (3x – 7x- 3x) + (3x^2 + 2x^2) + 2x^3 + (2x^4 + 2x^4) + 3x^5 + (5 + 7)\\⇔ A (x) = -7x + 5x^2 + 2x^3 + 4x^4 +  3x^5 + 12\\B (x) = (3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x + 5) – (2x^2 – 3x + 3x^5 + 2x^4 + 7)\\⇔ B (x) = 3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x + 5 – 2x^2 + 3x – 3x^5 – 2x^4 – 7\\⇔ B (x) = (3x^5 – 3x^5) + (3x^2 – 2x^2) + 3x^3 + (2x^4 – 2x^4) + (-7x + 3x) + (5 – 7)\\⇔ B (x) = x^2 + 3x^3 – 4x – 2$

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2. $A(x)=(3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x+5)+(2x^2-3x+3x^5 + 2x^4 +7)
   ⇔ A(x) = 3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x+5 +2x^2-3x+3x^5 + 2x^4 +7
   ⇔ A(x) =  (3x^5 + 3x^5) + (3x^2 + 2x^2) + 2x^3 + (2x^4 + 2x^4) – 7x + (5+7)$
   $⇔ A(x) = 6x^5 + 5x^2 + 2x^3 + 4x^4 – 7x + 12.$
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   $B(x)=(3x^5 + 3x^2 + 2x^3 + 2x^4 – 7x+5)-(2x^2-3x+3x^5 + 2x^4 +7)
   ⇔B(x)=3x^5+3x^2+2x^3+2x^4-7x+5-2x^2+3x-3x^5 – 2x^4 -7
   ⇔ B(x) = (3x^5 – 3x^5) + (3x^2 – 2x^2) + 2x^3 + (2x^4 – 2x^4) – 7x + (5-7)$
   $⇔ B(x) = x^2 + 2x^3 – 7x – 2.$

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