A -4/6 – 10/15 – 12/8 B 6/7 – (1/2004 – -6/7)

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1. Đáp án:

   `a,`

   `(-4)/6 – 10/15 – 12/8`

   `= (-4)/3 – 12/8`

   `= (-17)/6`

   `b,`

   `6/7 – (1/2004 – (-6)/7)`

   `= 6/7 – (1/2004 + 6/7)`

   `= 6/7 – 1/2004 – 6/7`

   `= (6/7 – 6/7) – 1/2004`

   `= 0 – 1/2004`

   `= (-1)/2004`

    

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2. Đáp án:

   $a) \frac{-17}{6}$

   $b) \frac{1}{2004}$

   Giải thích các bước giải:

   $a) \frac{-4}{6}-$ $\frac{10}{15}-$ $\frac{12}{8}$ 

   $=\frac{-4}{6}+$ $\frac{-10}{15}+$ $\frac{-12}{8}$

   $=\frac{-80+(-80)+(-180)}{120}$

   $=\frac{-340}{120}$

   $=\frac{-17}{6}$

   $b)\frac{6}{7}-$ $(\frac{1}{2004}-\frac{-6}{7})$

   $=\frac{6}{7}-($ $\frac{1}{2004}+$ $\frac{6}{7})$

   $=\frac{6}{7}-$ $\frac{1}{2004}-$ $\frac{6}{7}$

   $=\frac{6}{7}-$ $\frac{6}{7}-$ $\frac{1}{2004}$

   $=\frac{0}{7}-$ $\frac{1}{2004}$

   $=0-\frac{1}{2004}$

   $=\frac{-1}{2004}$

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