a) [6.(-1/3)mũ2-3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/2)mũ3 08/11/2021 Bởi Hailey a) [6.(-1/3)mũ2-3.(-1/3)+1]:(-1/3-1) b) (2/3)mũ3.(-3/4)mũ2.(-1)mũ2003 phần (2/5)mũ2.(-5/2)mũ3
a) `[6. (-1/3)^2 – 3. (-1/3) + 1] : (-1/3 -1)` `= [6. 1/9 – 3. (-1/3) + 1] : (-4/3)` `= [2/3 – (-1) + 1] : (-4/3)` `= 8/3 : (-4/3)` `= -2` b) `( (2/3)^3.(-3/4)^2.(-1)^2003)/((2/5)^2.(-5/2)^3` `= (8/27. (-9)/16) : (4/25. (-125)/8)` `= (-1)/6 : (-5)/2` `= 1/15` Bình luận
`\text{a)}` ` [ 6 . (-1/3)^2 – 3^2 . (-1/3) +1 ] : (-1/3 – 1)` `= [ 6 . 1/9 – 9 . 2/3] : (-4/3)` `= [ 6/9 – 18/3] : (-4/3)` `= [ 6/9 – 54/9] : (-4/3)` `= -16/3 . 3/-4` `= -16/-4` `= 4` `\text{b)}` `\frac{(2/3)^3 . (-3/4)^2 . (-1)^2003}{ (2/5)^2 . (-5/2)^3}` `= 6/9 . -9/16 : 4/25 . (-125/8)` `= 3/-4 : -5/ 2` `= -3/4 . 2/-5` `= 9/20` Bình luận
a) `[6. (-1/3)^2 – 3. (-1/3) + 1] : (-1/3 -1)`
`= [6. 1/9 – 3. (-1/3) + 1] : (-4/3)`
`= [2/3 – (-1) + 1] : (-4/3)`
`= 8/3 : (-4/3)`
`= -2`
b) `( (2/3)^3.(-3/4)^2.(-1)^2003)/((2/5)^2.(-5/2)^3`
`= (8/27. (-9)/16) : (4/25. (-125)/8)`
`= (-1)/6 : (-5)/2`
`= 1/15`
`\text{a)}`
` [ 6 . (-1/3)^2 – 3^2 . (-1/3) +1 ] : (-1/3 – 1)`
`= [ 6 . 1/9 – 9 . 2/3] : (-4/3)`
`= [ 6/9 – 18/3] : (-4/3)`
`= [ 6/9 – 54/9] : (-4/3)`
`= -16/3 . 3/-4`
`= -16/-4`
`= 4`
`\text{b)}`
`\frac{(2/3)^3 . (-3/4)^2 . (-1)^2003}{ (2/5)^2 . (-5/2)^3}`
`= 6/9 . -9/16 : 4/25 . (-125/8)`
`= 3/-4 : -5/ 2`
`= -3/4 . 2/-5`
`= 9/20`