a,(a-b) mũ3+(a+b) mũ3-2a mũ3 b,(x+2) mũ3+(x-2) mũ3+x mũ3-3x(x+2)(x-2) Rút gọn biểu thức sau 17/07/2021 Bởi Vivian a,(a-b) mũ3+(a+b) mũ3-2a mũ3 b,(x+2) mũ3+(x-2) mũ3+x mũ3-3x(x+2)(x-2) Rút gọn biểu thức sau
Giải thích các bước giải: a) `(a-b) ^3+(a+b) ^3-2a^3` `=a^3+3a^2b+3ab^2+b^3+a^3-3a^2b+3ab^2-b^3-2a^3` `=6ab^2` b) `(x+2) ^3+(x-2)^3+x ^3-3x(x+2)(x-2)` `=x^3+6x^2+12x+8+x^3-6x^2+12x-8-3x(x^2-4)` `=2x^3+24x-3x^3+12x` `=-x^3+36x` Bình luận
`a,(a-b)^3+(a+b)^3-2a^3` `=a^3-3a^2b+3ab^2-b^3+a^3+3a^2b+3ab^2+b^3-2a^3` `=(a^3+a^3-2a^3)+(-3a^2b+3a^2b)+(3ab^2+3ab^2)+(-b^3+b^3)` `=6ab^2` `b,(x+2)^3+(x-2)^3+x^3-3x(x+2)(x-2)` `=x^3+6x^2+12x+8+x^3-6x^2+12x-8+x^3-3x(x^2-4)` `=x^3+6x^2+12x+8+x^3-6x^2+12x-8+x^3-3x^3+12x` `=36x` Bình luận
Giải thích các bước giải:
a) `(a-b) ^3+(a+b) ^3-2a^3`
`=a^3+3a^2b+3ab^2+b^3+a^3-3a^2b+3ab^2-b^3-2a^3`
`=6ab^2`
b) `(x+2) ^3+(x-2)^3+x ^3-3x(x+2)(x-2)`
`=x^3+6x^2+12x+8+x^3-6x^2+12x-8-3x(x^2-4)`
`=2x^3+24x-3x^3+12x`
`=-x^3+36x`
`a,(a-b)^3+(a+b)^3-2a^3`
`=a^3-3a^2b+3ab^2-b^3+a^3+3a^2b+3ab^2+b^3-2a^3`
`=(a^3+a^3-2a^3)+(-3a^2b+3a^2b)+(3ab^2+3ab^2)+(-b^3+b^3)`
`=6ab^2`
`b,(x+2)^3+(x-2)^3+x^3-3x(x+2)(x-2)`
`=x^3+6x^2+12x+8+x^3-6x^2+12x-8+x^3-3x(x^2-4)`
`=x^3+6x^2+12x+8+x^3-6x^2+12x-8+x^3-3x^3+12x`
`=36x`