a) Tìm x, biết : x+1/3=1/4 b) Tính nhanh : 5/7.-2/11+5/7.-9/11 18/09/2021 Bởi Eva a) Tìm x, biết : x+1/3=1/4 b) Tính nhanh : 5/7.-2/11+5/7.-9/11
a) $x_{}$+$\frac{1}{3}$=$\frac{1}{4}$ ⇒ $x_{}$=$\frac{1}{4}$-$\frac{1}{3}$ ⇒ $x_{}$=$\frac{-1}{12}$ b) $\frac{5}{7}$.$\frac{-2}{11}$+$\frac{5}{7}$.$\frac{-9}{11}$ = $\frac{5}{7}$.($\frac{-2}{11}$+$\frac{-9}{11}$) = $\frac{5}{7}$.($-1_{}$) = $\frac{-5}{7}$ Bình luận
a) x + $\frac{1}{3}$ = $\frac{1}{4}$ ⇒ x + $\frac{4}{12}$ = $\frac{3}{12}$ ⇒ x = $\frac{3}{12}$ – $\frac{4}{12}$ ⇒ x = $\frac{3}{12}$ + $\frac{-4}{12}$ ⇒ x = $\frac{-1}{12}$ Vậy x = $\frac{-1}{12}$ b) $\frac{5}{7}$ . $\frac{-2}{11}$ + $\frac{5}{7}$ . $\frac{-9}{11}$ = $\frac{5}{7}$ . ( $\frac{-2}{11}$ + $\frac{-9}{11}$ ) = $\frac{5}{7}$ . $\frac{-11}{11}$ = $\frac{5}{7}$ . (-1) = $\frac{-5}{7}$ #Nothing is impossible# Bình luận
a) $x_{}$+$\frac{1}{3}$=$\frac{1}{4}$
⇒ $x_{}$=$\frac{1}{4}$-$\frac{1}{3}$
⇒ $x_{}$=$\frac{-1}{12}$
b) $\frac{5}{7}$.$\frac{-2}{11}$+$\frac{5}{7}$.$\frac{-9}{11}$
= $\frac{5}{7}$.($\frac{-2}{11}$+$\frac{-9}{11}$)
= $\frac{5}{7}$.($-1_{}$)
= $\frac{-5}{7}$
a) x + $\frac{1}{3}$ = $\frac{1}{4}$
⇒ x + $\frac{4}{12}$ = $\frac{3}{12}$
⇒ x = $\frac{3}{12}$ – $\frac{4}{12}$
⇒ x = $\frac{3}{12}$ + $\frac{-4}{12}$
⇒ x = $\frac{-1}{12}$
Vậy x = $\frac{-1}{12}$
b) $\frac{5}{7}$ . $\frac{-2}{11}$ + $\frac{5}{7}$ . $\frac{-9}{11}$
= $\frac{5}{7}$ . ( $\frac{-2}{11}$ + $\frac{-9}{11}$ )
= $\frac{5}{7}$ . $\frac{-11}{11}$
= $\frac{5}{7}$ . (-1)
= $\frac{-5}{7}$
#Nothing is impossible#