Al2O3 -> Al ->Al2(SO4)3 -> AlCl3 ->Al(OH)3 C->CO->CO2->NA2CO3->CaCO3 NaCl->Cl2->FeCl3->BaCl2->AgCl

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1. Bài giải :

   – Dãy thứ nhất :

   $2Al_2O_3\xrightarrow{đpnc}4Al↓+3O_2 ↑$

   `2Al+3H_2SO_4→Al_2(SO_4)_3+3H_2↑`

   `Al_2(SO_4)_3+3BaCl_2→3BaSO_4↓+2AlCl_3`

   `AlCl_3+3NaOH→Al(OH)_3↓+3NaCl`

   – Dãy thứ hai :

   $C+CO_2\xrightarrow{t^o}2CO $

   `2CO+O_2→2CO_2`

   `CO_2+2NaOH→Na_2CO_3+H_2O`

   `Na_2CO_3+CaCl_2→CaCO_3↓+2NaCl`

   – Dãy thứ ba :

   $2NaCl+2H_2O\xrightarrow{đpddcmn}2NaOH+H_2↑+Cl_2↑ $

   $2Fe3+3Cl_2\xrightarrow{t^o}2FeCl_3 $

   `2FeCl_3+3Ba(OH)_2→2Fe(OH)_3↓+3BaCl_2`

   `BaCl_2+2AgNO_3→2AgCl↓+Ba(NO_3)_2`

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2. Đáp án:a) 2Al2O3→4Al+3O2 ↑

   2Al+3H2SO4→Al2(SO4)3+3H2 ↑Al2(SO4)3+3BaCl2→2AlCl3+3BaSO4 ↓

   AlCl3+3NaOH→Al(OH)3 ↓ +3NaCl

   b) C+CO_2→ 2CO

   2CO+O2→2CO2

   Na2O+CO2→Na2CO3

   Ca(OH)2+Na2CO3→CaCO3+2NaOH

   c)2H2O+2NaCl→Cl2+H2+2NaOH3

   Cl2+2Fe→2FeCl3

   3Ba(OH)2+2FeCl3→3BaCl3+2Fe(OH)

   3BaCl2+Ag2SO4→2AgCl+BaSO4

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