Bài 1 : c) ( 3$\frac{1}{4}$ – 6$\frac{5}{9}$ ) × 2$\frac{2}{17}$ d) ( $\frac{-4}{7}$ + $\frac{1}{3}$ ) ÷ $\frac{9}{5}$ + ( $\frac{2}{3}$ – $\frac{3}

Bởi

Bài 1 :
c) ( 3$\frac{1}{4}$ – 6$\frac{5}{9}$ ) × 2$\frac{2}{17}$
d) ( $\frac{-4}{7}$ + $\frac{1}{3}$ ) ÷ $\frac{9}{5}$ + ( $\frac{2}{3}$ – $\frac{3}{7}$ ) ÷ $\frac{9}{5}$

0 bình luận về “Bài 1 : c) ( 3$\frac{1}{4}$ – 6$\frac{5}{9}$ ) × 2$\frac{2}{17}$ d) ( $\frac{-4}{7}$ + $\frac{1}{3}$ ) ÷ $\frac{9}{5}$ + ( $\frac{2}{3}$ – $\frac{3}”

  1. Giải thích các bước giải:

    `c)`
    `(3 1/4 -6 5/9). 2 2/17`
    `=(13/4 – 59/9). 36/17`
    `=13/4 . 36/17 – 59/9 . 36/17`
    `=117/17-236/17`
    `=-119/17`
    `=-7`
    `d)`
    `(-4/7+1/3):9/5+(2/3-3/7):9/5`
    `(-4/7+1/3). 5/9+(2/3-3/7). 5/9`
    `=(-4/7+1/3+2/3-3/7). 5/9`
    `=[(-4/7-3/7)+(1/3+2/3)]. 5/9`
    `=(-7/7+3/3). 5/9`
    `=(-1+1). 5/9`
    `=0 . 5/9`
    `=0`

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  2. `\text{c)}`

    `( 3 1/4 – 6 5/9 ) × 2 2/17`

    `= ( 13/4 –   59/9 ) × 36/17`

    `= -119/36 × 36/17`

    `=   -7`

    `\text{d)}`

    `(-4/7 +1/3) : 9/5 + (2/3 – 3/7) : 9/5`

    `= 5/9(-4/7+1/3) + 5/9(2/3-3/7)`

    `= 5/9(-4/7 +1/3 + 2/3 – 3/7)`

    `= 5/9[(-4/7 -3/7) + (1/3+2/3) ]`

    `= 5/9 (-1 +1)`

    `= 5/9 . 0`

    `= 0`  

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