Bài 1 :
c) ( 3$\frac{1}{4}$ – 6$\frac{5}{9}$ ) × 2$\frac{2}{17}$
d) ( $\frac{-4}{7}$ + $\frac{1}{3}$ ) ÷ $\frac{9}{5}$ + ( $\frac{2}{3}$ – $\frac{3}{7}$ ) ÷ $\frac{9}{5}$
Bài 1 : c) ( 3$\frac{1}{4}$ – 6$\frac{5}{9}$ ) × 2$\frac{2}{17}$ d) ( $\frac{-4}{7}$ + $\frac{1}{3}$ ) ÷ $\frac{9}{5}$ + ( $\frac{2}{3}$ – $\frac{3}
By Hailey
Giải thích các bước giải:
`c)`
`(3 1/4 -6 5/9). 2 2/17`
`=(13/4 – 59/9). 36/17`
`=13/4 . 36/17 – 59/9 . 36/17`
`=117/17-236/17`
`=-119/17`
`=-7`
`d)`
`(-4/7+1/3):9/5+(2/3-3/7):9/5`
`(-4/7+1/3). 5/9+(2/3-3/7). 5/9`
`=(-4/7+1/3+2/3-3/7). 5/9`
`=[(-4/7-3/7)+(1/3+2/3)]. 5/9`
`=(-7/7+3/3). 5/9`
`=(-1+1). 5/9`
`=0 . 5/9`
`=0`
`\text{c)}`
`( 3 1/4 – 6 5/9 ) × 2 2/17`
`= ( 13/4 – 59/9 ) × 36/17`
`= -119/36 × 36/17`
`= -7`
`\text{d)}`
`(-4/7 +1/3) : 9/5 + (2/3 – 3/7) : 9/5`
`= 5/9(-4/7+1/3) + 5/9(2/3-3/7)`
`= 5/9(-4/7 +1/3 + 2/3 – 3/7)`
`= 5/9[(-4/7 -3/7) + (1/3+2/3) ]`
`= 5/9 (-1 +1)`
`= 5/9 . 0`
`= 0`