bài 1: Cho G= 2 mũ 2+ 2 mũ 4+ 2 mũ 6 + 2 mũ 8 +………+ 2 mũ 94+ 2 mũ 96 Tìm số dư khi G:17 20/11/2021 Bởi Kennedy bài 1: Cho G= 2 mũ 2+ 2 mũ 4+ 2 mũ 6 + 2 mũ 8 +………+ 2 mũ 94+ 2 mũ 96 Tìm số dư khi G:17
Đáp án: $0$ Giải thích các bước giải: Ta có:$G=2^2+2^4+2^6+2^8+…+2^{94}+2^{96}$ $\to G=(2^2+2^6+2^{10}+…+2^{94})+(2^4+2^8+…+2^{96})$ $\to G=((2^2+2^6)+(2^{10}+2^{14})+…+(2^{90}+2^{94}))+((2^4+2^8)+…+(2^{92}+2^{96}))$ $\to G=(2^2(1+2^4)+2^{10}(1+2^4)+…+2^{90}(1+2^4))+(2^4(1+2^4)+…+2^{92}(1+2^4))$ $\to G=(1+2^4)(2^2+2^{10}+…+2^{90})+(1+2^4)(2^4+…+2^{92})$ $\to G=(1+2^4)((2^2+2^{10}+…+2^{90})+(2^4+…+2^{92}))$ $\to G=17((2^2+2^{10}+…+2^{90})+(2^4+…+2^{92}))$ $\to G\quad\vdots\quad 17$ $\to G$ chia $17$ dư $0$ Bình luận
Giải thích các bước giải: G=2^2+2^4+2^6+2^8+…………+2^94+2^96 G=2+2^2+2^4+2^6+2^8+…………+2^90+2^92+2^94+2^96 =2+(2^2+2^6)+(2^4+2^8)+……………+(2^90+2^94)+(2^92+2^96) =2+2^2(1+16)+2^4(1+16)+………….+2^90(1+16)+2^92(1+16) =2+2^2.17+2^4.17+……………+2^90.17+2^92.1 ⇒số dư cuả G:17 là 2 Bình luận
Đáp án: $0$
Giải thích các bước giải:
Ta có:
$G=2^2+2^4+2^6+2^8+…+2^{94}+2^{96}$
$\to G=(2^2+2^6+2^{10}+…+2^{94})+(2^4+2^8+…+2^{96})$
$\to G=((2^2+2^6)+(2^{10}+2^{14})+…+(2^{90}+2^{94}))+((2^4+2^8)+…+(2^{92}+2^{96}))$
$\to G=(2^2(1+2^4)+2^{10}(1+2^4)+…+2^{90}(1+2^4))+(2^4(1+2^4)+…+2^{92}(1+2^4))$
$\to G=(1+2^4)(2^2+2^{10}+…+2^{90})+(1+2^4)(2^4+…+2^{92})$
$\to G=(1+2^4)((2^2+2^{10}+…+2^{90})+(2^4+…+2^{92}))$
$\to G=17((2^2+2^{10}+…+2^{90})+(2^4+…+2^{92}))$
$\to G\quad\vdots\quad 17$
$\to G$ chia $17$ dư $0$
Giải thích các bước giải:
G=2^2+2^4+2^6+2^8+…………+2^94+2^96
G=2+2^2+2^4+2^6+2^8+…………+2^90+2^92+2^94+2^96
=2+(2^2+2^6)+(2^4+2^8)+……………+(2^90+2^94)+(2^92+2^96)
=2+2^2(1+16)+2^4(1+16)+………….+2^90(1+16)+2^92(1+16)
=2+2^2.17+2^4.17+……………+2^90.17+2^92.1
⇒số dư cuả G:17 là 2