Bài 1 : Tìm x a, $\frac{-2}{15}$ – x = $\frac{-3}{10}$ b, x + $\frac{1}{3}$ = $\frac{2}{5}$ – ( $\frac-{1}{3}$ ) c, $\frac{3}{7}$ – x = $\frac{1}{4

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1. Đáp án:

   ${a,x=}$ $\dfrac{1}{6}$ 

   ${b,x=}$ $\dfrac{2}{5}$

   ${c,x=}$ $-\dfrac{59}{140}$

   Giải thích các bước giải:

   ${a,}$ $-\dfrac{2}{15}-x=$ $-\dfrac{3}{10}$ 

   ${x=}$ $-\dfrac{2}{15}-$ $(-\dfrac{3}{10})$

   ${x=}$ $-\dfrac{2}{15}+$ $\dfrac{3}{10}$

   ${x=}$ $\dfrac{1}{6}$

   ${b,x+}$ $\dfrac{1}{3}=$ $\dfrac{2}{5}-$ $(-\dfrac{1}{3})$

   ${x+}$ $\dfrac{1}{3}=$ $\dfrac{2}{5}+$ $\dfrac{1}{3}$

   ${x+}$ $\dfrac{1}{3}=$ $\dfrac{11}{15}$

   ${x=}$ $\dfrac{11}{15}-$ $\dfrac{1}{3}$

   ${x=}$ $\dfrac{2}{5}$

   ${c,}$ $\dfrac{3}{7}-x=$ $\dfrac{1}{4}-$ $(-\dfrac{3}{5})$

   $\dfrac{3}{7}-x=$ $\dfrac{1}{4}+$ $\dfrac{3}{5}$

   $\dfrac{3}{7}-x=$ $\dfrac{17}{20}$

   ${x=}$ $\dfrac{3}{7}-$ $\dfrac{17}{20}$

   ${x=}$ $-\dfrac{59}{140}$  

   ~Xin hay nhất~

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2. a,$\frac{-2}{15}$ -x=$\frac{-3}{10}$ 

                               x=a,$\frac{-2}{15}$-$\frac{-3}{10}$ 

                               x=$\frac{1}{6}$ 

   b,x+$\frac{1}{3}$ =$\frac{2}{5}$-(-3)

      x+$\frac{1}{3}$=$\frac{17}{5}$

      x                      =$\frac{17}{5}$-$\frac{1}{3}$

      x                      =$\frac{46}{15}$ 

   c,$\frac{3}{7}$ -x=$\frac{1}{4}$ -($\frac{-5}{3}$ )

     $\frac{3}{7}$-x=$\frac{23}{12}$

                          x=$\frac{3}{7}$-$\frac{23}{12}$

                          x=$\frac{-131}{84}$

   cho mình ctlhn nhé^-^

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