Bài 2: Tìm x bt: 5/3-x+1/3=5/10 x-5/3=1/2+1/3 x-(1-1/4)=2/3 x-5=1/3+1/4 x-(1/5+1/4)=7/10

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1. @Học để làm gì ?

   `_Sói__`

   *Bài làm :

   a,`5/3-x+1/3=5/10`

   `5/3 + 1/3 – x = 5/10`

   `6/3 – x = 5/10`

   `2 – x = 1/2`

   `x= 2 – 1/2`

   `x = 3/2`

   b,`x-5/3=1/2+1/3`

   `x – 5/3 = 5/6`

   `x = 5/6 + 5/3`

   `x =15/6`

   `x = 5/2`

   c, `x-(1-1/4)=2/3`

   `x – 3/4 = 2/3`

   `x = 2/3 + 3/4`

   `x = 17/12`

   d,`x-5=1/3+1/4`

   `x – 5 = 7/12`

   `x = 7/12 + 5`

   `x= 67/12`

   `x-(1/5+1/4)=7/10`

   `x – 9/20 = 7/10`

   `x = 7/10 + 9/20`

   `x = 23/20`

   `#Study well`

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2. Đáp án:

    

   Giải thích các bước giải:

   + ) $\frac{5}{3}$ – x + $\frac{1}{3}$ = $\frac{5}{10}$ 

   $\frac{5}{3}$ + $\frac{1}{3}$ – x = $\frac{5}{10}$ 

   2 – x  = $\frac{5}{10}$ 

   x = 2 – $\frac{5}{10}$ 

   x = $\frac{3}{2}$ 

   + ) x – $\frac{5}{3}$ = $\frac{1}{2}$ + $\frac{1}{3}$ 

    x = $\frac{5}{3}$ + $\frac{1}{3}$ + $\frac{1}{2}$ 

   x = 2 + $\frac{1}{2}$ 

   x = $\frac{5}{2}$ 

   + ) x – ( 1 – $\frac{1}{4}$ ) = $\frac{2}{3}$ 

   x – 1 + $\frac{1}{4}$ = $\frac{2}{3}$ 

   x + $\frac{1}{4}$ = $\frac{2}{3}$ + 1

   x + $\frac{1}{4}$ = $\frac{5}{3}$

   x = $\frac{5}{3}$ – $\frac{1}{4}$ 

   x = $\frac{17}{12}$ 

   + ) x – 5 = $\frac{1}{3}$ + $\frac{1}{4}$ 

   x – 5 = $\frac{7}{12}$ 

   x = $\frac{7}{12}$ + 5

   x = $\frac{67}{12}$ 

   + ) x – ( $\frac{1}{5}$ + $\frac{1}{4}$ ) = $\frac{7}{10}$ 

   x – $\frac{1}{5}$ – $\frac{1}{4}$ = $\frac{7}{10}$ 

   x = $\frac{7}{10}$ + $\frac{1}{5}$ + $\frac{1}{4}$

   x = $\frac{9}{10}$ + $\frac{1}{4}$

   x = $\frac{23}{20}$ 

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