Bài 2 ; Tính
a, $\frac{24.47-23}{24+47.23}$
b, $\frac{3+\frac{3}{7} -\frac{3}{11}+ \frac{3}{1001}-\frac{3}{13} }{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7} -\frac{9}{11}+9 }$
Mn giúp mik với ạ
Bài 2 ; Tính
a, $\frac{24.47-23}{24+47.23}$
b, $\frac{3+\frac{3}{7} -\frac{3}{11}+ \frac{3}{1001}-\frac{3}{13} }{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7} -\frac{9}{11}+9 }$
Mn giúp mik với ạ
a, Ta có: $\frac{24.47-23}{24+47.23}$
= $\frac{24.47-23}{47.23+47-23}$
= $\frac{24.47-23}{47.24-23}$
=1
b, Ta có:
$\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{\frac{9}{1001}-\frac{9}{13}+\frac{9}{7}-\frac{1}{11}+9}$
= $\frac{3+\frac{3}{7}-\frac{3}{11}+\frac{3}{1001}-\frac{3}{13}}{3(\frac{3}{1001}-\frac{3}{13}+\frac{3}{7}-\frac{3}{11}+3)}$
= $\frac{1}{3}$
`a, {24.47-23}/{24+47.23}`
`={(23+1).47-23}/{24+47.23}`
`={23.47+47-23}/{24+47.23}`
`={23.47+24}/{24+47.23}`
`={24+23.47}/{24+23.47}`
`=1`
`b,{3+3/7-3/11+3/1001-3/13}/{9/1001-9/13+9/7-9/11+9}`
`={3+3. 1/7-3. 1/11+3. 1/1001-3. 1/13}/{9. 1/1001-9. 1/13+9. 1/7-9. 1/11+9}`
`={3.(1/7-1/11+1/1001-1/13)}/{9.(1/1001-1/13+1/7-1/11)}`
`={3.(1/7-1/11+1/1001-1/13)}/{9.(1/7-1/11+1/1001-1/13)}`
`=3/9`
`=1/3`