Bài 25 : Tính một cách hợp lý.
c) 7 + 15 : [55 – 2.(3.12 – 11)]
d) [164 – (12.5 + 4)] : 4 + 46
e) 25.29 + 5^2.2^2.15 + 11.25
f) 2016^0+ 1^2016.(3^2.3 – 2^4: 8)
h) {47 – [736 : (5 – 3)^4]}.2017
g) 2^2.3^1– (1^2017 + 2017^0) : |-2|
Bài 25 : Tính một cách hợp lý.
c) 7 + 15 : [55 – 2.(3.12 – 11)]
d) [164 – (12.5 + 4)] : 4 + 46
e) 25.29 + 5^2.2^2.15 + 11.25
f) 2016^0+ 1^2016.(3^2.3 – 2^4: 8)
h) {47 – [736 : (5 – 3)^4]}.2017
g) 2^2.3^1– (1^2017 + 2017^0) : |-2|
Đáp án:
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Giải thích các bước giải:
c) 7 + 15 : [ 55 – 2 . ( 3 . 12 – 11 ) ]
= 7 + 15 : [ 55 – 2 . ( 36 – 11 ) ]
= 7 + 15 : [ 55 – 2 . 25 ]
= 7 + 15 : [ 55 – 50 ]
= 7 + 15 : 5
= 7 + 3
= 10
d) [ 164 – ( 12 . 5 + 4 ) ] : 4 + 46
= [ 164 – ( 60 + 4 ) ] : 4 + 46
= [ 164 – 64 ] : 4 + 46
= 100 : 4 + 46
= 25 + 46
= 71
e) 25 . 29 + 5² . 2² . 15 + 11 . 25
= 25 . 29 + 25 . 4 . 15 + 11 . 25
= 25 . ( 29 + 11 ) + 25 . 4 . 15
= 25 . 40 + 25 . 60
= 25 . ( 40 + 60 )
= 25 . 100
= 2500
f) 2016^0 + 1^2016 . ( 3² . 3 – 2^4 : 8 )
= 1 + 1 . ( 9 . 3 – 16 : 8 )
= 1 + 1 . ( 27 – 2 )
= 1 + 1 . 25
= 1 + 25
= 26
h) { 47 – [ 736 : ( 5 – 3 )^4 ] } . 2017
= { 47 – [ 736 : 2^4 ] } . 2017
= { 47 – [ 736 : 16 ] } . 2017
= { 47 – 46 } . 2017
= 1 . 2017
= 2017
g) 2² . 3^1 – ( 1^2017 + 2017^0 ) : /-2/
= 4 . 3 – ( 1 + 1 ) : 2
= 12 – 2 : 2
= 12 – 1
= 11
$c)7+15:[55-2(3.12-11)]$
$=7+15:[55-2(36-11)]$
$=7+15:[55-2.25]$
$=7+15:[55-50]$
$=7+15:5$
$=7+5$
$=12$
$d)[164-(12.5+4)]:4+46$
$=[164-(60+4)]:4+46$
$=[164-64]:4+46$
$=100:4+46$
$=25+46$
$=71$
$e)25.29+5^2.2^2.15+11.25$
$=25.29+25.4+15.25$
$=25(29+4+11)$
$=25.44$
$=1100$
$f)$`2016^0+1^{2016}(3^2 .3-2^4:8)`
$=1+1(9.3-16:8)$
$=1+1(27-2)$
$=1+1.25$
$=26$
$h)$`{47-[736:(5-3)^4]}.2017`
`={47-[736:2^4]}.2017`
`={47-[736:16]}.2017`
`={47-46}.2017`
`=1.2017`
`=2017`
`g)2^2. 3^1-(1^{2017}+2017^0):|-2|`
$=4.3-(1+1):2$
$=12-2:2$
$=12-1$
$=11$