C= (4/3 + 8/3)*(7/4-6/4): (6/5+12/5+1/5) D= 1/1*4+1/4*7+1/7*10+…+1/31*34 E= 1*2/1^2*2*3/2^2*3*4/3^2*4*5/4^2*5*6/5^2 Chú ý: Tất cả đều là phân số. dò

0 bình luận về “C= (4/3 + 8/3)*(7/4-6/4): (6/5+12/5+1/5) D= 1/1*4+1/4*7+1/7*10+…+1/31*34 E= 1*2/1^2*2*3/2^2*3*4/3^2*4*5/4^2*5*6/5^2 Chú ý: Tất cả đều là phân số. dò”

1. Đáp án:

   $\begin{array}{l}
   C = \left( {\frac{4}{3} + \frac{8}{3}} \right).\left( {\frac{7}{4} – \frac{6}{4}} \right):\left( {\frac{6}{5} + \frac{{12}}{5} + \frac{1}{5}} \right)\\
    = \frac{{4 + 8}}{3}.\frac{{7 – 6}}{4}:\frac{{6 + 12 + 1}}{5}\\
    = \frac{{12}}{3}.\frac{1}{4}.\frac{5}{{19}}\\
    = \frac{5}{{19}}\\
   D = \frac{1}{{1.4}} + \frac{1}{{4.7}} + \frac{1}{{7.10}} + … + \frac{1}{{31.34}}\\
    \Rightarrow 3.D = \frac{3}{{1.4}} + \frac{3}{{4.7}} + \frac{3}{{7.10}} + … + \frac{3}{{31.34}}\\
    \Rightarrow 3.D = \frac{{4 – 1}}{{1.4}} + \frac{{7 – 4}}{{4.7}} + \frac{{10 – 7}}{{7.10}} + … + \frac{{34 – 31}}{{31.34}}\\
    \Rightarrow 3.D = 1 – \frac{1}{4} + \frac{1}{4} – \frac{1}{7} + \frac{1}{7} – \frac{1}{{10}} + … + \frac{1}{{31}} – \frac{1}{{34}}\\
    \Rightarrow 3.D = 1 – \frac{1}{{34}} = \frac{{33}}{{34}}\\
    \Rightarrow D = \frac{{33}}{{34}}.\frac{1}{3} = \frac{{11}}{{34}}\\
   E = \frac{{1.2}}{{{1^2}}}.\frac{{2.3}}{{{2^2}}}.\frac{{3.4}}{{{3^2}}}.\frac{{4.5}}{{{4^2}}}.\frac{{5.6}}{{{5^2}}}\\
    = \frac{2}{1}.\frac{3}{2}.\frac{4}{3}.\frac{5}{4}.\frac{6}{5}\\
    = 6
   \end{array}$

   Bình luận