C1: 1/24 : (3x – 2) =-3 2/-45 : 5.(-3 – 2x)=3 3/x.(x + 7) =0 4/(x + 12).(x-3) =0 5/x.(2 + x).(7 – x) =0 6/(x-1).(x+2).(-x – 3) =0

C1:
1/24 : (3x – 2) =-3
2/-45 : 5.(-3 – 2x)=3
3/x.(x + 7) =0
4/(x + 12).(x-3) =0
5/x.(2 + x).(7 – x) =0
6/(x-1).(x+2).(-x – 3) =0

0 bình luận về “C1: 1/24 : (3x – 2) =-3 2/-45 : 5.(-3 – 2x)=3 3/x.(x + 7) =0 4/(x + 12).(x-3) =0 5/x.(2 + x).(7 – x) =0 6/(x-1).(x+2).(-x – 3) =0”

  1. 1  24 : (3x – 2) =-3

    ⇔3x – 2=24 : (-3)

    ⇔3x – 2=-8

    ⇔3x      =-8+2

    ⇔3x      =6

    ⇔3x      =6 : 3

    ⇔  x      =1

    Vậy x=1

    2   -45 : 5.(-3 – 2x)=3

    ⇔-9.(-3 – 2x)=3

    ⇔        -3 – 2x      =3:(-9)

    ⇔        -3 – 2x      =-1/3

    ⇔         – 2x          =-1/3+3

    ⇔         – 2x          =8/3

    ⇔              x          =8/3:(-2)

    ⇔              x          =-4/3

    3    x.(x + 7) =0

    ⇔\(\left[ \begin{array}{l}x=0\\x + 7=0\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=0\\x=-7\end{array} \right.\) 

    Vây x=0; x=-7

     4 (x + 12).(x-3) =0

    ⇔\(\left[ \begin{array}{l}x + 12=0\\x-3=0\end{array} \right.\)⇔\(\left[ \begin{array}{l}x=-12\\x=3\end{array} \right.\) 

    Vây x=-12; x=3

     5  x.(2 + x).(7 – x) =0

    \(\left[ \begin{array}{l}x=0\\2 + x=0\end{array} \right.\)

        hoặc 7 – x=0

    ⇔\(\left[ \begin{array}{l}x=0\\x=-2\end{array} \right.\) 

        hoặc x=7

    Vậy x=0;x=-2;x=7

     6 (x-1).(x+2).(-x – 3) =0

    \(\left[ \begin{array}{l}x-1=0\\ x+2 =0\end{array} \right.\)

        hoặc x -3 =0

    ⇔\(\left[ \begin{array}{l}x=1\\x=-2\end{array} \right.\) 

        hoặc x=3

    Vậy x=1;x=-2;x=3

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  2. 1.

    $24:(3x-2)=-3$

    $3x-2=24:(-3)$

    $3x-2=-8$

    $3x=(-8)+2$

    $3x=-6$

    $x=(-6):3$

    $→ x=-2$

    2. 

    $-45:5.(-3-2x)=3$

    $-9.(-3-2x)=3$

    $-3-2x=3:(-9)$ 

    $-3-2x=0,3$

    $2x=(-3)-0,3$

    $2x=-3,3$

    $→ x=-1,65$

    (Số 0,3 mình chỉ lấy xấp xỉ thôi nhé!)

    3. 

    $x.(x+7)=0$

    $2x+7x=0$

    $9x=0$

    $→ x=0$

    4. 

    $(x+12).(x-3)=0$

    $x+12=0⇒x=0-12=-12$

    $x-3=0⇒x=0+3=3$

    $\textrm{→ x={-12;3}}$

    5. 

    $x.(2+x).(7-x)=0$

    $x.(2+x)$

    $2x+2x=0$

    $4x=0$

    $→ x=0$

    $7-x=0$

    $x=7-0$ 

    $→ x=7$

    $\textrm{→ x={0;7}}$

    6.

    $(x-1).(x+2).(-x-3)=0$

    $x-1=0$

    $→ x=0+1=1$

    $x+2=0$

    $→x=0-2=-2$

    $-x-3=0$

    $-x=0+3$

    $-x=3$

    $→ x=-3$

    $\textrm{→ x={1;-2;-3}}$

     

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