Các bạn làm giúp mk bài này nha. Viết công thức cấu tạo của hợp chất: ch4, c2h6, c3h8, c4h10, c5h12, c2h5cl, ch4o, ch3br, c2h4, c2h2, c3h6, c4h8, c2h

Em tham khảo nha:

\(\begin{array}{l}
C{H_4}:H – C{H_2} – H\\
{C_2}{H_6}:C{H_3} – C{H_3}\\
{C_3}{H_8}:C{H_3} – C{H_2} – C{H_3}\\
{C_4}{H_{10}}:\\
C{H_3} – C{H_2} – C{H_2} – C{H_3}\\
C{H_3} – CH(C{H_3}) – C{H_3}\\
{C_5}{H_{12}}:\\
C{H_3} – C{H_2} – C{H_2} – C{H_2} – C{H_3}\\
C{H_3} – CH(C{H_3}) – C{H_2} – C{H_3}\\
C{H_3} – C{(C{H_3})_2} – C{H_3}\\
{C_2}{H_5}Cl:C{H_3} – C{H_2}Cl\\
C{H_4}O:C{H_3} – OH\\
C{H_3}Br:H – C{H_2} – Br\\
{C_2}{H_4}:C{H_2} = C{H_2}\\
{C_2}{H_2}:CH \equiv CH\\
{C_3}{H_6}:C{H_2} = CH – C{H_3}\\
{C_4}{H_8}:\\
C{H_2} = CH – C{H_2} – C{H_3}\\
C{H_2} = C(C{H_3}) – C{H_3}\\
C{H_3} – CH = CH – C{H_3}\\
{C_2}{H_4}B{r_2}:C{H_2}Br – C{H_2}Br\\
{C_2}{H_2}B{r_2}:CHBr = CHBr\\
{C_2}{H_5}Br:C{H_3} – C{H_2}Br\\
C{H_3}Cl:Cl – C{H_2} – H
\end{array}\)