Câu 1: So sánh P và Q: P = 2016/2017 + 2017/2018 + 2018/2019 Q = 2016+2017+2018/2017+2018+2019. Câu 2: Tìm x: ( 2,7x – 1 1/2x ) : 2/7 = -21/4 ( 1 1/2

Câu 1: So sánh P và Q:
P = 2016/2017 + 2017/2018 + 2018/2019
Q = 2016+2017+2018/2017+2018+2019.
Câu 2: Tìm x:
( 2,7x – 1 1/2x ) : 2/7 = -21/4
( 1 1/2 là hỗn số nhân vs x nha, 2,7 là số thập phân )

0 bình luận về “Câu 1: So sánh P và Q: P = 2016/2017 + 2017/2018 + 2018/2019 Q = 2016+2017+2018/2017+2018+2019. Câu 2: Tìm x: ( 2,7x – 1 1/2x ) : 2/7 = -21/4 ( 1 1/2”

  1. Câu 1:

    Ta có:

    ` P = 2016/2017 + 2017/2018 + 2018/2019 `

    ` <=> P = \frac{2016}{2017 + 2018 + 2019} + \frac{2017}{2018 + 2017 + 2019} + \frac{2018}{2019 + 2017 + 2018} `

    Vì ` \frac{2016}{2017+2018+2019} > \frac{2016+2017+2018}{2017+2018+2019} `

    ` \frac{2017}{2017+2018+2019} > \frac{2016+2017+2018}{2017+2018+2019} `

    ` \frac{2018}{2017+2018+2019} > \frac{2016+2017+2018}{2017+2018+2019} `

    ` => \frac{2016}{2017 + 2018 + 2019} + \frac{2017}{2018 + 2017 + 2019} + \frac{2018}{2019 + 2017 + 2018} > \frac{2016+2017+2018}{2017+2018+2019} `

    ` => P > Q `

    Câu 2:

    ` (2,7x – 1 1/2 x) : 2/7 = -21/4 `

    ` => 27/10 x – 3/2 x = -21/4 . 2/7 `

    ` => 6/5 x = -3/2 `

    ` => x = -3/2 . 5/6 `

    ` => x = -5/4 `

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  2. Đáp án:

     $1)  P>Q$

    $2)
     x=\dfrac{-5}{4}$

    Giải thích các bước giải:

     $1)P=\dfrac{2016}{2017}+\dfrac{2017}{2018}+\dfrac{2018}{2019}\\
    Q=\dfrac{2016+2017+2018}{2017+2018+2019}\\
    =\dfrac{2016}{2017+2018+2019}+\dfrac{2017}{2017+2018+2019}+\dfrac{2018}{2017+2018+2019}\\$
    Do $2017<2017+2018+2019$
    $\Rightarrow \dfrac{2016}{2017}>\dfrac{2016}{2017+2018+2019}(1)\\
    2018<2017+2018+2019\\
    \Rightarrow \dfrac{2017}{2018}>\dfrac{2017}{2017+2018+2019}(2)\\
    2019<2017+2018+2019\\
    \Rightarrow \dfrac{2018}{2019}>\dfrac{2018}{2017+2018+2019}(3)\\
    (1),(2),(3)\Rightarrow \dfrac{2016}{2017}+\dfrac{2017}{2018}+\dfrac{2018}{2019}>\dfrac{2016}{2017+2018+2019}+\dfrac{2017}{2017+2018+2019}+\dfrac{2018}{2017+2018+2019}\\
    \Leftrightarrow P>Q$

    $2)
    (2,7x-1\dfrac{1}{2}x):\dfrac{2}{7}=\dfrac{-21}{4}\\
    \Leftrightarrow \left ( \dfrac{27}{10}-\dfrac{3}{2} \right )x.\dfrac{7}{2}=\dfrac{-21}{4}\\
    \Leftrightarrow \left ( \dfrac{27}{10}-\dfrac{15}{10} \right )x.\dfrac{7}{2}=\dfrac{-21}{4}\\
    \Leftrightarrow \dfrac{12}{10}x.\dfrac{7}{2}=\dfrac{-21}{4}\\
    \Leftrightarrow \dfrac{21}{5}x=\dfrac{-21}{4}\\
    \Leftrightarrow x=\dfrac{-21}{4}.\dfrac{5}{21}\\
    \Leftrightarrow x=\dfrac{-5}{4}$

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