Bạn tham khảo : $A =1+2^2+2^4+2^6+…….+2^{100}$ $2^2A = 2^2+2^4+2^6+2^8 + … +2^{102}$ $4A -A = (2^2+2^4+2^6+2^8 + … +2^{102}) – (1+2^2+2^4+2^6+…….+2^{100})$ $3A = 2^{102} -1$ $A = \dfrac{2^{102}-1}{3}$ Bình luận
Bạn tham khảo :
$A =1+2^2+2^4+2^6+…….+2^{100}$
$2^2A = 2^2+2^4+2^6+2^8 + … +2^{102}$
$4A -A = (2^2+2^4+2^6+2^8 + … +2^{102}) – (1+2^2+2^4+2^6+…….+2^{100})$
$3A = 2^{102} -1$
$A = \dfrac{2^{102}-1}{3}$