Cho 5,85 NaCl vào dung dịch AgNO3 thấy xuất hiện mg kiết tủa tính m ( Na=23, Cl=35,5, Ag=108, N=14, O=16)

PTPƯ:

$
\begin{array}{l}
{\hspace{0.33em}\hspace{0.33em}{NaCl}\mathrm{{+}}{AgNO}_{3}\mathrm{\longrightarrow}{AgCl}\mathrm{{+}}{NaNO}_{3}}\\
{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}{nNaCl}\mathrm{{=}}{nAgCl}\mathrm{{=}}\frac{5\mathrm{,}\mathrm{85}}{{\mathrm{23}}\mathrm{{+}}{\mathrm{35}}{\mathrm{,}}{5}}\mathrm{{=}}{0}{\mathrm{,}}{1}{\mathrm{(}}{mol}{\mathrm{)}}}\\
{\hspace{0.33em}\hspace{0.33em}\hspace{0.33em}{mAgCl}\mathrm{{=}}{0}{\mathrm{,}}{1}{\mathrm{.(}}{\mathrm{108}}\mathrm{{+}}{\mathrm{35}}{\mathrm{,}}{5}{\mathrm{)}}\mathrm{{=}}{\mathrm{14}}{\mathrm{,}}{\mathrm{35}}{\mathrm{(}}{g}{\mathrm{)}}}
\end{array}
$