Cho biểu thức A = 2x/x^2+2x – 8/x^2-4 + 2/x-2 (x khác 0 , x khác _+ 2) giúp mik vs

Giải thích các bước giải:

$\begin{array}{l} \frac{{2x}}{{{x^2} + 2x}} – \frac{8}{{{x^2} – 4}} + \frac{2}{{x – 2}}\\  = \frac{{2x}}{{x(x + 2)}} – \frac{8}{{{x^2} – 4}} + \frac{2}{{x – 2}}\\  = \frac{2}{{x + 2}} – \frac{8}{{{x^2} – 4}} + \frac{2}{{x – 2}}\\  = \frac{{2(x – 2) – 8 + 2(x + 2)}}{{(x + 2)(x – 2)}}\\  = \frac{{2x – 4 – 8 + 2x + 4}}{{(x – 2)(x + 2)}}\\  = \frac{{4x – 8}}{{(x – 2)(x + 2)}}\\  = \frac{{4(x – 2)}}{{(x – 2)(x + 2)}} = \frac{4}{{x + 2}} \end{array}$