Cho f(x) = x⁶+x⁵-3x²-2x²-x+1 g(x) = -x⁶-x⁵-x⁴-x³-x²-x-1 h(x) = 2x²-x+2 a, Tính f(x)+g(x)+h(x) b, Tính f(x)-g(x)-h(x) c, Tính f(x)+g(x)

0 bình luận về “Cho f(x) = x⁶+x⁵-3x²-2x²-x+1 g(x) = -x⁶-x⁵-x⁴-x³-x²-x-1 h(x) = 2x²-x+2 a, Tính f(x)+g(x)+h(x) b, Tính f(x)-g(x)-h(x) c, Tính f(x)+g(x)”

1. Đáp án:

   `a,f(x)+g(x)+h(x)=-x^4-x^3-4x^2-3x+2`

   `b,f(x)+g(x)+h(x)=2x^6+2x^5+x^4+x^3-6x^2+x`

   `c,f(x)+g(x)-h(x)=-x^4-x^3-8x^2-x-2`

   `d,k(x)=2x^6+2x^5+x^4+x^3-2x^2-x+4`

   Giải thích các bước giải:

   `a,` Ta có :

   `f(x)+g(x)+h(x)=(x^6+x^5-3x^2-2x^2-x+1)+(-x^6-x^5-x^4-x^3-x^2-x-1)+(2x^2-x+2)`

   `=>f(x)+g(x)+h(x)=x^6+x^5-3x^2-2x^2-x+1-x^6-x^5-x^4-x^3-x^2-x-1+2x^2-x+2`

   `=>f(x)+g(x)+h(x)=-x^4-x^3-4x^2-3x+2`

   `b,` Ta có :

   `f(x)-g(x)-h(x)=(x^6+x^5-3x^2-2x^2-x+1)-(-x^6-x^5-x^4-x^3-x^2-x-1)-(2x^2-x+2)`

   `⇒f(x)+g(x)+h(x)=x^6+x^5-3x^2-2x^2-x+1+x^6+x^5+x^4+x^3+x^2+x+1-2x^2+x-2`

   `=>f(x)+g(x)+h(x)=2x^6+2x^5+x^4+x^3-6x^2+x`

   `c,` Ta có :

   `f(x)+g(x)-h(x)=(x^6+x^5-3x^2-2x^2-x+1)+(-x^6-x^5-x^4-x^3-x^2-x-1)-(2x^2-x+2)`

   `⇒f(x)+g(x)-h(x)=x^6+x^5-3x^2-2x^2-x+1-x^6-x^5-x^4-x^3-x^2-x-1-2x^2+x-2`

   `=>f(x)+g(x)-h(x)=-x^4-x^3-8x^2-x-2`

   `d,` Ta có :

   `f(x)-k(x)=g(x)-h(x)`

   `=>k(x)=f(x)-g(x)+h(x)`

   `=>k(x)=(x^6+x^5-3x^2-2x^2-x+1)-(-x^6-x^5-x^4-x^3-x^2-x-1)+(2x^2-x+2)`

   `=>k(x)=x^6+x^5-3x^2-2x^2-x+1+x^6+x^5+x^4+x^3+x^2+x+1+2x^2-x+2`

   `=>k(x)=2x^6+2x^5+x^4+x^3-2x^2-x+4`

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2. a, f(x)+g(x)+h(x)=(x⁶+x⁵-3x²-2x²-x+1)+(-x⁶-x⁵-x⁴-x³-x²-x-1)+(2x²-x+2)

   ⇒f(x)+g(x)+h(x)=x⁶+x⁵-3x²-2x²-x+1−x⁶-x⁵-x⁴-x³-x²-x-1+2x²−x+2

   ⇒f(x)+g(x)+h(x)=-x⁴-x³-4x²+2

   b, f(x)-g(x)-h(x)=(x⁶+x⁵-3x²-2x²-x+1)-(-x⁶-x⁵-x⁴-x³-x²-x-1)-(2x²-x+2)

   ⇒f(x)+g(x)+h(x)=x⁶+x⁵-3x²-2x²-x+1+x⁶+x⁵+x⁴+x³+x²+x+1+2x²+x-2

   ⇒f(x)+g(x)+h(x)=2x⁶+2x⁵+x⁴+x³−6x²+x

   c, f(x)+g(x)-h(x)=(x6+x5-3×2-2×2-x+1)+(-x6-x5-x4-x3-x2-x-1)-(2×2-x+2)

   ⇒f(x)+g(x)-h(x)=x6+x5-3×2-2×2-x+1-x6-x5-x4-x3-x2-x-1-2×2+x-2

   ⇒f(x)+g(x)−h(x)=−x4−x3−8×2−x−2

   d, f(x)-k(x)=g(x)-h(x)

   ⇒k(x)=(x6+x5−3×2−2×2−x+1)−(−x6−x5−x4−x3−x2−x−1)+(2×2−x+2)

   ⇒k(x)=x6+x5−3×2−2×2−x+1+x6+x5+x4+x3+x2+x+1+2×2−x+2

   ⇒k(x)=2×6+2×5+x4+x3−2×2−x+4

   xin hay nhất cho nhóm ạ 

    

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