cho R1 song song R2 chứng minh rằng 1/Rtđ=1/R+ 1/R2=> Rtđ=R1.R2 10/08/2021 Bởi Camila cho R1 song song R2 chứng minh rằng 1/Rtđ=1/R+ 1/R2=> Rtđ=R1.R2
Đáp án + Giải thích các bước giải: $\dfrac{1}{R_{tđ}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$ $ \to \dfrac{1}{R_{tđ}}=\dfrac{R_2}{R_1.R_2}+\dfrac{R_1}{R_1.R_2}$ $ \to \dfrac{1}{R_{tđ}}=\dfrac{R_1+R_2}{R_1.R_2}$ $ \to R_{tđ}=\dfrac{R_1.R_2.1}{R_1+R_2}$ $ \to R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}$ Bình luận
$\begin{array}{l}\text{Ta có:}\\\dfrac{1}{R_{tđ}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\to \dfrac{1}{R_{tđ}}=\dfrac{R_2}{R_1R_2}+\dfrac{R_1}{R_1R_2}\\\to \dfrac{1}{R_{tđ}}=\dfrac{R_1+R_2}{R_1R_2}\\\to \dfrac{1}{\dfrac{1}{R_{tđ}}}=\dfrac{1}{\dfrac{R_1+R_2}{R_1R_2}}\\\to R_{tđ}=\dfrac{R_1R_2}{R_1+R_2}\end{array}$ Bình luận
Đáp án + Giải thích các bước giải:
$\dfrac{1}{R_{tđ}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$
$ \to \dfrac{1}{R_{tđ}}=\dfrac{R_2}{R_1.R_2}+\dfrac{R_1}{R_1.R_2}$
$ \to \dfrac{1}{R_{tđ}}=\dfrac{R_1+R_2}{R_1.R_2}$
$ \to R_{tđ}=\dfrac{R_1.R_2.1}{R_1+R_2}$
$ \to R_{tđ}=\dfrac{R_1.R_2}{R_1+R_2}$
$\begin{array}{l}\text{Ta có:}\\\dfrac{1}{R_{tđ}}=\dfrac{1}{R_1}+\dfrac{1}{R_2}\\\to \dfrac{1}{R_{tđ}}=\dfrac{R_2}{R_1R_2}+\dfrac{R_1}{R_1R_2}\\\to \dfrac{1}{R_{tđ}}=\dfrac{R_1+R_2}{R_1R_2}\\\to \dfrac{1}{\dfrac{1}{R_{tđ}}}=\dfrac{1}{\dfrac{R_1+R_2}{R_1R_2}}\\\to R_{tđ}=\dfrac{R_1R_2}{R_1+R_2}\end{array}$