Chuyên dòi các hệ cơ số sau sang dạng thập phân: 1. 1111: =?10 2. IBE16 = ?10 3.3AF16 = ?,0 26/07/2021 Bởi Melanie Chuyên dòi các hệ cơ số sau sang dạng thập phân: 1. 1111: =?10 2. IBE16 = ?10 3.3AF16 = ?,0
1. $1111_{2}$ =$2^{3}$*1 + $2^{2}$*1 + $2^{1}$*1 + $2^{0}$*1 = $15_{10}$ 2. $IBE_{16}$ = $16^{2}$*18 + $16^{1}$*11 + $16^{0}$*14 = $4789_{10}$ 3. $3AF_{16}$ = $16^{2}$*3 + $16^{1}$*10 + $16^{0}$*15 = $943_{10}$ Bình luận
$1111_{2}$ = 1.$2^{3}+ 1. 2^2 +1. 2^1 + 1.2^0$ = $15_{10}$ $3AF_{16}= 3.16^2+ 10.16^1 + 15.16^0$ =$1168_{10}$ $1BE_{16}$ = $1.16^2 + 11.16^1 + 14.16^0$= $446_{10}$ Bình luận
1. $1111_{2}$ =$2^{3}$*1 + $2^{2}$*1 + $2^{1}$*1 + $2^{0}$*1 = $15_{10}$
2. $IBE_{16}$ = $16^{2}$*18 + $16^{1}$*11 + $16^{0}$*14 = $4789_{10}$
3. $3AF_{16}$ = $16^{2}$*3 + $16^{1}$*10 + $16^{0}$*15 = $943_{10}$
$1111_{2}$ = 1.$2^{3}+ 1. 2^2 +1. 2^1 + 1.2^0$ = $15_{10}$
$3AF_{16}= 3.16^2+ 10.16^1 + 15.16^0$ =$1168_{10}$
$1BE_{16}$ = $1.16^2 + 11.16^1 + 14.16^0$= $446_{10}$