d)3x-(-36)=-27;e)|x+25|-12=27;f)|x-2|=8;g)2/x=-8/20 14/09/2021 Bởi Genesis d)3x-(-36)=-27;e)|x+25|-12=27;f)|x-2|=8;g)2/x=-8/20
`d ) 3x – ( – 36 ) = -27` `3x + 36 = -27` `3x = -27 – 36 = -63` `x = -63 : 3 = -21 ` Vậy ` x = -21` `e ) | x + 25 | – 12 = 27` ` | x + 25 | = 39` `⇒` \(\left[ \begin{array}{l}x+25 = 39⇔ x = 14 \\x+ 25 = -39 ⇔ x = 64\end{array} \right.\) `f ) | x – 2 | = 8` `⇒` \(\left[ \begin{array}{l}x-2=8⇔x = 10\\x-2 =-8 ⇔ x = -6\end{array} \right.\) `g ) 2/x = -8/(20)` `⇒ -8 xx x = 2 xx 20` ` – 8x = 40` `x = 40 : ( – 8 ) = -5` Bình luận
$#Đáp án + Giải thích các bước giải:$ `d)3x-(-36)=-27` `→3x+36=-27` `→3x=-27-36` `→3x=-63` `→x=-63:3` `→x=-21` Vậy `x=-21` —————————– `e)|x+25|-12=27` `→|x+25|=27+12` `→|x+25|=39` `↔`\(\left[ \begin{array}{l}x+25=39\\x+25=-39\end{array} \right.\) `↔`\(\left[ \begin{array}{l}x=39-25\\x=-39-25\end{array} \right.\) `↔`\(\left[ \begin{array}{l}x=14\\x=-64\end{array} \right.\) Vậy `x∈{14;-64}` ——————————- `f)|x-2| = 8` `→`\(\left[ \begin{array}{l}x-2=8\\x-3=-8\end{array} \right.\) `→`\(\left[ \begin{array}{l}x=8+2\\x=-8+2\end{array} \right.\) `→`\(\left[ \begin{array}{l}x=10\\x=-6\end{array} \right.\) Vậy `x∈{10;-6}` —————————— `g)2/x = -8/20` `→-8.x=2.20` `→-8.x=40` `→x=40:-8` `→x=-5` Vậy `x=-5` —————————— $#Cam$ $#XIN HAY NHẤT CHO NHÓM AK$ Bình luận
`d ) 3x – ( – 36 ) = -27`
`3x + 36 = -27`
`3x = -27 – 36 = -63`
`x = -63 : 3 = -21 `
Vậy ` x = -21`
`e ) | x + 25 | – 12 = 27`
` | x + 25 | = 39`
`⇒` \(\left[ \begin{array}{l}x+25 = 39⇔ x = 14 \\x+ 25 = -39 ⇔ x = 64\end{array} \right.\)
`f ) | x – 2 | = 8`
`⇒` \(\left[ \begin{array}{l}x-2=8⇔x = 10\\x-2 =-8 ⇔ x = -6\end{array} \right.\)
`g ) 2/x = -8/(20)`
`⇒ -8 xx x = 2 xx 20`
` – 8x = 40`
`x = 40 : ( – 8 ) = -5`
$#Đáp án + Giải thích các bước giải:$
`d)3x-(-36)=-27`
`→3x+36=-27`
`→3x=-27-36`
`→3x=-63`
`→x=-63:3`
`→x=-21`
Vậy `x=-21`
—————————–
`e)|x+25|-12=27`
`→|x+25|=27+12`
`→|x+25|=39`
`↔`\(\left[ \begin{array}{l}x+25=39\\x+25=-39\end{array} \right.\)
`↔`\(\left[ \begin{array}{l}x=39-25\\x=-39-25\end{array} \right.\)
`↔`\(\left[ \begin{array}{l}x=14\\x=-64\end{array} \right.\)
Vậy `x∈{14;-64}`
——————————-
`f)|x-2| = 8`
`→`\(\left[ \begin{array}{l}x-2=8\\x-3=-8\end{array} \right.\)
`→`\(\left[ \begin{array}{l}x=8+2\\x=-8+2\end{array} \right.\)
`→`\(\left[ \begin{array}{l}x=10\\x=-6\end{array} \right.\)
Vậy `x∈{10;-6}`
——————————
`g)2/x = -8/20`
`→-8.x=2.20`
`→-8.x=40`
`→x=40:-8`
`→x=-5`
Vậy `x=-5`
——————————
$#Cam$
$#XIN HAY NHẤT CHO NHÓM AK$