đọc chuỗi phản ứng c2h2 – c4h4-c4h6-ca su buna ch4-c2h2-c2h4-pe ch4-c2h2-c2h6-c2h5cl 21/10/2021 Bởi Kaylee đọc chuỗi phản ứng c2h2 – c4h4-c4h6-ca su buna ch4-c2h2-c2h4-pe ch4-c2h2-c2h6-c2h5cl
Các phản ứng ứng xảy ra: a) \(2{C_2}{H_2}\xrightarrow{{{t^o}}}CH \equiv C – CH = C{H_2}\) \(CH \equiv C – CH = C{H_2} + {H_2}\xrightarrow{{Pd,{t^o}}}C{H_2} = CH – CH – C{H_2}\) \(nC{H_2} = CH – CH – C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – CH = CH – C{H_2} – )_n}\) b) \(2C{H_4}\xrightarrow{{{{1500}^o}C,l\ln }}CH \equiv CH + 3{H_2}\) \(CH \equiv CH + {H_2}\xrightarrow{{Pd,{t^o}}}C{H_2} = C{H_2}\) \(nC{H_2} = C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – C{H_2} – )_n}\) c) \(2C{H_4}\xrightarrow{{{{1500}^o}C,l\ln }}CH \equiv CH + 3{H_2}\) \(CH \equiv CH + 2{H_2}\xrightarrow{{Ni,{t^o}}}C{H_3} – C{H_3}\) \(C{H_3} – C{H_3} + C{l_2}\xrightarrow{{as}}C{H_3} – C{H_2}Cl + HCl\) Bình luận
Các phản ứng ứng xảy ra:
a) \(2{C_2}{H_2}\xrightarrow{{{t^o}}}CH \equiv C – CH = C{H_2}\)
\(CH \equiv C – CH = C{H_2} + {H_2}\xrightarrow{{Pd,{t^o}}}C{H_2} = CH – CH – C{H_2}\)
\(nC{H_2} = CH – CH – C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – CH = CH – C{H_2} – )_n}\)
b)
\(2C{H_4}\xrightarrow{{{{1500}^o}C,l\ln }}CH \equiv CH + 3{H_2}\)
\(CH \equiv CH + {H_2}\xrightarrow{{Pd,{t^o}}}C{H_2} = C{H_2}\)
\(nC{H_2} = C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – C{H_2} – )_n}\)
c)
\(2C{H_4}\xrightarrow{{{{1500}^o}C,l\ln }}CH \equiv CH + 3{H_2}\)
\(CH \equiv CH + 2{H_2}\xrightarrow{{Ni,{t^o}}}C{H_3} – C{H_3}\)
\(C{H_3} – C{H_3} + C{l_2}\xrightarrow{{as}}C{H_3} – C{H_2}Cl + HCl\)