Toán $\frac{2x^{2}-2x+3 }{x}$ tìm giá trị x để bt nguyên 26/07/2021 By Raelynn $\frac{2x^{2}-2x+3 }{x}$ tìm giá trị x để bt nguyên
` (2 x^2 − 2 x + 3)/ x ∈ Z ` `=(2 x^2 − 2 + 3)/x ∈ Z` `= [x ( x − 2 ) + 3]/x ∈ Z ` `=x-2+3/x ∈ Z` `=>3` $\vdots$ x` `⇒ x ∈ Ư ( 3 ) = { ± 1 ; ± 3 }` Trả lời
`(2x^2-2x+3)/x ∈Z`
`=2x-2+3/x ∈Z`
`=x(x-2)+3/x ∈Z`
`⇒3/x ∈Z`
`⇒x∈Ư_((3))={±1; ±3}`
` (2 x^2 − 2 x + 3)/ x ∈ Z `
`=(2 x^2 − 2 + 3)/x ∈ Z`
`= [x ( x − 2 ) + 3]/x ∈ Z `
`=x-2+3/x ∈ Z`
`=>3` $\vdots$ x`
`⇒ x ∈ Ư ( 3 ) = { ± 1 ; ± 3 }`