$\frac{2a+9}{a+3}$ -$\frac{5n+17}{a+3}$ -$\frac{3a}{a+3}$ giúp mk vs 30/07/2021 Bởi Eva $\frac{2a+9}{a+3}$ -$\frac{5n+17}{a+3}$ -$\frac{3a}{a+3}$ giúp mk vs
$\dfrac{2a+9}{a+3} – \dfrac{5a+17}{a+3} – \dfrac{3a}{a+3}$ $= \dfrac{(2a+9)-(5a+17) – 3a}{a+3}$ $= \dfrac{2a + 9 – 5a – 17 – 3a}{a+3}$ $= \dfrac{(2n – 5a – 3a)+ (9- 17)}{a+3}$ $= \dfrac{-6a – 8}{a+3}$ $= \dfrac{8 – 6a}{a+3}$. Bình luận
Đáp án:
Giải thích các bước giải:
$\dfrac{2a+9}{a+3} – \dfrac{5a+17}{a+3} – \dfrac{3a}{a+3}$
$= \dfrac{(2a+9)-(5a+17) – 3a}{a+3}$
$= \dfrac{2a + 9 – 5a – 17 – 3a}{a+3}$
$= \dfrac{(2n – 5a – 3a)+ (9- 17)}{a+3}$
$= \dfrac{-6a – 8}{a+3}$
$= \dfrac{8 – 6a}{a+3}$.