Toán \frac{-5}{3}$ – | 2x-1| : $\frac{3}{5 }$ = -2 05/08/2021 By Aaliyah \frac{-5}{3}$ – | 2x-1| : $\frac{3}{5 }$ = -2
Đáp án+Giải thích các bước giải: `-5/3-|2x-1|:3/5=-2` `\to -|2x-1|:3/5=-2+5/3` `\to -|2x-1|:3/5=-1/3` `\to -|2x-1|=-1/3.(3)/5` `\to -|2x-1|=-1/5` `\to |2x-1|=1/5` `\to 2x-1=+-1/5` TH 1: `2x-1=1/5` `\to 2x=1/5+1` `\to 2x=6/5` `\to x=6/5:2` `\to x=3/5` TH 2: `2x-1=-1/5` `\to 2x=-1/5+1` `\to 2x=4/5` `\to x=4/5:2` `\to x=2/5` Vậy `x\in\{3/5;2/5\}` Trả lời
Đáp án: tham khảo ≈ω Giải thích các bước giải: `-5/3-|2x-1|:3/5=-2` `-|2x-1|:3/5=-2+5/3` `-|2x-1|:3/5=-1/3` `-|2x-1|=-1/3.(3)/5` `|2x-1|=1/5` \(\left[ \begin{array}{l}2x-1 = \dfrac{1}{5}\\2x-1=\dfrac{-1}{5}\end{array} \right.\) \(\left[ \begin{array}{l}2x = \dfrac{1}{5} +1\\2x=\dfrac{-1}{5}+1\end{array} \right.\) \(\left[ \begin{array}{l}2x = \dfrac{6}{5} \\2x=\dfrac{4}{5}\end{array} \right.\) \(\left[ \begin{array}{l}x = \dfrac{6}{5}:2 \\x=\dfrac{4}{5}:2\end{array} \right.\) \(\left[ \begin{array}{l}x = \dfrac{3}{5} \\x=\dfrac{2}{5}\end{array} \right.\) vậy `x\in{\frac{3}{5};\frac{2}{5}}` Trả lời
Đáp án+Giải thích các bước giải:
`-5/3-|2x-1|:3/5=-2`
`\to -|2x-1|:3/5=-2+5/3`
`\to -|2x-1|:3/5=-1/3`
`\to -|2x-1|=-1/3.(3)/5`
`\to -|2x-1|=-1/5`
`\to |2x-1|=1/5`
`\to 2x-1=+-1/5`
TH 1:
`2x-1=1/5`
`\to 2x=1/5+1`
`\to 2x=6/5`
`\to x=6/5:2`
`\to x=3/5`
TH 2:
`2x-1=-1/5`
`\to 2x=-1/5+1`
`\to 2x=4/5`
`\to x=4/5:2`
`\to x=2/5`
Vậy `x\in\{3/5;2/5\}`
Đáp án:
tham khảo ≈ω
Giải thích các bước giải:
`-5/3-|2x-1|:3/5=-2`
`-|2x-1|:3/5=-2+5/3`
`-|2x-1|:3/5=-1/3`
`-|2x-1|=-1/3.(3)/5`
`|2x-1|=1/5`
\(\left[ \begin{array}{l}2x-1 = \dfrac{1}{5}\\2x-1=\dfrac{-1}{5}\end{array} \right.\)
\(\left[ \begin{array}{l}2x = \dfrac{1}{5} +1\\2x=\dfrac{-1}{5}+1\end{array} \right.\)
\(\left[ \begin{array}{l}2x = \dfrac{6}{5} \\2x=\dfrac{4}{5}\end{array} \right.\)
\(\left[ \begin{array}{l}x = \dfrac{6}{5}:2 \\x=\dfrac{4}{5}:2\end{array} \right.\)
\(\left[ \begin{array}{l}x = \dfrac{3}{5} \\x=\dfrac{2}{5}\end{array} \right.\)
vậy `x\in{\frac{3}{5};\frac{2}{5}}`