Giải phương trình : ( 2x + 3)^2 = ( 2x + 3 )( x-1) 03/12/2021 Bởi Raelynn Giải phương trình : ( 2x + 3)^2 = ( 2x + 3 )( x-1)
Đáp án: (2x+3)^2=(2x+3)(x-1) (2x+3)(2x+3)-(2x+3)(x-1)=0 (2x+3)(2x+3-x+1)=0 (2x+3)(x+4)=0 2x+3=0 hoặc x+4=0 x=-3/2 x=-4 Bình luận
$(2x+3)^2=(2x+3)(x-1)\\\Leftrightarrow (2x+3)^2-(2x+3) (x-1)\\\Leftrightarrow (2x+3)(2x+3-x+1) =0\\\Leftrightarrow (2x+3) (x+4) =0\\\Leftrightarrow \left[\begin{array} {} 2x+3=0\\x+4=0\end{array} \right.\\\Leftrightarrow \left[\begin{array} {} x=-\dfrac{3} {2} \\x=-4\end{array}\right.$ Bình luận
Đáp án:
(2x+3)^2=(2x+3)(x-1)
(2x+3)(2x+3)-(2x+3)(x-1)=0
(2x+3)(2x+3-x+1)=0
(2x+3)(x+4)=0
2x+3=0 hoặc x+4=0
x=-3/2 x=-4
$(2x+3)^2=(2x+3)(x-1)\\\Leftrightarrow (2x+3)^2-(2x+3) (x-1)\\\Leftrightarrow (2x+3)(2x+3-x+1) =0\\\Leftrightarrow (2x+3) (x+4) =0\\\Leftrightarrow \left[\begin{array} {} 2x+3=0\\x+4=0\end{array} \right.\\\Leftrightarrow \left[\begin{array} {} x=-\dfrac{3} {2} \\x=-4\end{array}\right.$