Giải phương trình : | – 4 . 5x |= 6 + 2 . 5x 05/11/2021 Bởi Lyla Giải phương trình : | – 4 . 5x |= 6 + 2 . 5x
$|-4.5x|=6+2.5x$ $⇔ |-20x|=6+10x$ $\textrm{Nếu x<0}$ $⇒ -20x=6+10x$ $⇔ -20x-10x=6$ $⇔ -30x=6$ $⇔ x=\dfrac{-1}{5}$ $\textrm{Nếu x>0}$ $⇒ 20x=6+10x$ $⇔ 20x-10x=6$ $⇔ 10x=6$ $⇔ x=\dfrac{3}{5}$ Bình luận
$|-4.5x|=6+2.5x$ $⇔|-20x|=6+10x$ (1) Nếu $x>0$ Khi đó: $(1)⇔20x=6+10x$ $⇔20x-10x=6$ $⇔10x=6$ $⇔x=\dfrac{3}{5}$ Nếu $x<0$ Khi đó: $(1)⇔-20x=6+10x$ $⇔-20x-10x=6$ $⇔-30x=6$ $⇔x=\dfrac{-1}{5}$ Vậy $S=\{\dfrac{3}{5};\dfrac{-1}{5}\}$ Bình luận
$|-4.5x|=6+2.5x$
$⇔ |-20x|=6+10x$
$\textrm{Nếu x<0}$
$⇒ -20x=6+10x$
$⇔ -20x-10x=6$
$⇔ -30x=6$
$⇔ x=\dfrac{-1}{5}$
$\textrm{Nếu x>0}$
$⇒ 20x=6+10x$
$⇔ 20x-10x=6$
$⇔ 10x=6$
$⇔ x=\dfrac{3}{5}$
$|-4.5x|=6+2.5x$
$⇔|-20x|=6+10x$ (1)
Nếu $x>0$
Khi đó:
$(1)⇔20x=6+10x$
$⇔20x-10x=6$
$⇔10x=6$
$⇔x=\dfrac{3}{5}$
Nếu $x<0$
Khi đó:
$(1)⇔-20x=6+10x$
$⇔-20x-10x=6$
$⇔-30x=6$
$⇔x=\dfrac{-1}{5}$
Vậy $S=\{\dfrac{3}{5};\dfrac{-1}{5}\}$