Giair giúp mik nha mn $\left[\begin{array}{ccc}2.x+3\end{array}\right]$ $^{2}$ =$\frac{25}{81}$ 03/07/2021 Bởi Margaret Giair giúp mik nha mn $\left[\begin{array}{ccc}2.x+3\end{array}\right]$ $^{2}$ =$\frac{25}{81}$
Đáp án: $x = \frac{-11}{9}$ hoặc $x = \frac{-16}{9}$ Giải thích các bước giải: $(2x + 3)² = \frac{25}{81}$ $→(2x + 3)² = (± \frac{5}{9})²$ $→\left[ \begin{array}{l}2x+3=\frac{5}{9}\\2x+3=\frac{-5}{9}\end{array} \right.$ $→\left[ \begin{array}{l}2x=\frac{-22}{9}\\2x=\frac{-32}{9}\end{array} \right.$ $→\left[ \begin{array}{l}x=\frac{-11}{9}\\x=\frac{-16}{9}\end{array} \right.$ Vậy $x = \frac{-11}{9}$ hoặc $x = \frac{-16}{9}$ Bình luận
(2x+3)²=`25/81` →|2x+3|=`5/9` →\(\left[ \begin{array}{l}2x+3=5/9\\2x+3=-5/9\end{array} \right.\) →\(\left[ \begin{array}{l}x=-11/9\\x=-16/9\end{array} \right.\) Bình luận
Đáp án:
$x = \frac{-11}{9}$ hoặc $x = \frac{-16}{9}$
Giải thích các bước giải:
$(2x + 3)² = \frac{25}{81}$
$→(2x + 3)² = (± \frac{5}{9})²$
$→\left[ \begin{array}{l}2x+3=\frac{5}{9}\\2x+3=\frac{-5}{9}\end{array} \right.$
$→\left[ \begin{array}{l}2x=\frac{-22}{9}\\2x=\frac{-32}{9}\end{array} \right.$
$→\left[ \begin{array}{l}x=\frac{-11}{9}\\x=\frac{-16}{9}\end{array} \right.$
Vậy $x = \frac{-11}{9}$ hoặc $x = \frac{-16}{9}$
(2x+3)²=`25/81`
→|2x+3|=`5/9`
→\(\left[ \begin{array}{l}2x+3=5/9\\2x+3=-5/9\end{array} \right.\)
→\(\left[ \begin{array}{l}x=-11/9\\x=-16/9\end{array} \right.\)