giup mik vs Tim x: a, (2x-1)^3=125 b,3^x-1=27 c,26x:4=32 d,3^x:3^2=243 e,6x^3-8=40 h,4^2x-1:4=16

giup mik vs Tim x:
a, (2x-1)^3=125
b,3^x-1=27
c,26x:4=32
d,3^x:3^2=243
e,6x^3-8=40
h,4^2x-1:4=16

0 bình luận về “giup mik vs Tim x: a, (2x-1)^3=125 b,3^x-1=27 c,26x:4=32 d,3^x:3^2=243 e,6x^3-8=40 h,4^2x-1:4=16”

  1. a, `(2x-1)^3`=125

    => `(2x-1)^3` = `5^3`

    => 2x-1 = 5

    => 2x = 6

    => x = 3

    b,`3^(x-1)`=27

    => `3^(x-1)` = `3^3`

    => x – 1 = 3

    => x = 4

    c,26x : 4=32

    => 26x = 128

    => x = `128/26`

    => x = `64/13`

    d,`3^x` : `3^2`=243

    => 3^(x-2) = `3^5`

    => x – 2 = 5

    => x = 7

    e,6`x^3` – 8=40

    =>6`x^3` = 48

    => `x^3` = 8

    => `x^3` = `2^3`

    => x = 2

    h,`4^(2x- 1)` : 4=16

    => `4^(2x- 1)` = 64

    => `4^(2x- 1)` = `4^3`

    => 2x – 1 = 3

    => 2x = 4

    => x = 2

    XIN HAY NHẤT Ạ

     

    Bình luận
  2. a) `(2x-1)³=125`

    `⇒ (2x-1)³=5³`

    `⇒ 2x-1=5`

    `⇒ 2x=6`

    `⇒ x=3`

    b) `3^(x-1)=27`

    `⇒ 3^(x-1)=3^3`

    `⇒ x-1=3`

    `⇒ x=4`

    d) `3^x :3^2=243`

    `⇒ 3^x :3²=3^5`

    `⇒ 3^x=3³`

    `⇒ x=3`

    e) `6x^3-8=40`

    `⇒ 6x^3=48`

    `⇒ x^3=8`

    `⇒ x^3=2^3`

    `⇒ x=2`

    h) `4^(2x-1):4=16`

    `⇒ 4^(2x-1)=64`

    `⇒ 4^(2x-1)=4^3`

    `⇒ 2x-1=3`

    `⇒ 2x=4`

    `⇒ x=2`

    Bình luận

Viết một bình luận