giúp mình giải bài: sin10x – cos6x = căn 3(sin6x – cos10x)

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1. $\begin{array}{l}
   \sin 10x – \cos 6x = \sqrt 3 \left( {\sin 6x – \cos 10x} \right)\\
   \Leftrightarrow \sin 10x + \sqrt 3 \cos 10x = \sqrt 3 \sin 6x + \cos 6x\\
   \Leftrightarrow \frac{1}{2}\sin 10x + \frac{{\sqrt 3 }}{2}\cos 10x = \frac{{\sqrt 3 }}{2}\sin 6x + \frac{1}{2}\cos 6x\\
   \Leftrightarrow \sin \left( {10x + \frac{\pi }{3}} \right) = \sin \left( {6x + \frac{\pi }{6}} \right)\\
   \Leftrightarrow \left[ \begin{array}{l}
   10x + \frac{\pi }{3} = 6x + \frac{\pi }{6} + k2\pi \\
   10x + \frac{\pi }{3} = \pi – 6x – \frac{\pi }{6} + k2\pi
   \end{array} \right.\\
   \Leftrightarrow \left[ \begin{array}{l}
   4x = – \frac{\pi }{6} + k2\pi \\
   16x = \frac{\pi }{2} + k2\pi
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   x = – \frac{\pi }{{24}} + \frac{{k\pi }}{2}\\
   x = \frac{\pi }{{32}} + \frac{{k\pi }}{8}
   \end{array} \right.
   \end{array}$

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