Giúp với !!! $\sqrt{3}$x – $\sqrt{2}$x = $\sqrt{3}$ + $\sqrt{2}$

`sqrt3x-sqrt2x=sqrt3+sqrt2`

`<=>x(sqrt3-sqrt2)=sqrt3+sqrt2`

`<=>x=(sqrt3+sqrt2)/(sqrt3-sqrt2)`

`<=>x=((sqrt3+sqrt2)^2)/((sqrt3-sqrt2)(sqrt3+sqrt2))`

`<=>x=(sqrt3+sqrt2)^2/(3-2)`

`<=>x=(sqrt3+sqrt2)^2`

`<=>x=5+2sqrt6`

Vậy PT có nghiệm `x=5+2sqrt6`.