Hoa tan 4g hh Fe va 1kloai htri ll vao dd thi HCL thu duoc 2.24 lit khi H2. Neu chi dung 2.4 g kl htri ll thi dung 0.5 mol hcl. Tim ten kloai htri ll
Hoa tan 4g hh Fe va 1kloai htri ll vao dd thi HCL thu duoc 2.24 lit khi H2. Neu chi dung 2.4 g kl htri ll thi dung 0.5 mol hcl. Tim ten kloai htri ll
Đáp án:
Magie
Giải thích các bước giải:
\(\begin{array}{l}
Fe + 2HCl \to FeC{l_2} + {H_2}\\
M + 2HCl \to MC{l_2} + {H_2}\\
n{H_2} = \frac{{2,24}}{{22,4}} = 0,1\,mol\\
Mhh = \frac{4}{{0,1}} = 40g/mol\\
= > MM < 40g/mol(1)\\
nM = \frac{{nHCl}}{2} = 0,25\,mol\\
MM > \frac{{2,4}}{{0,25}} = 9,6(2)\\
(1),(2) = > MM = 24g/mol\\
= > M:Mg
\end{array}\)