Hoàn thành chương trình phản ứng sau: CH3COONA -> CH4 -> C2H2 -> CH2=CH-CL -> POLI ( vinyl clorua) 17/07/2021 Bởi Jade Hoàn thành chương trình phản ứng sau: CH3COONA -> CH4 -> C2H2 -> CH2=CH-CL -> POLI ( vinyl clorua)
Các phản ứng xảy ra: \(C{H_3}COONa + NaOH\xrightarrow{{CaO,{t^o}}}C{H_4} + N{a_2}C{O_3}\) \(2C{H_4}\xrightarrow{{{{1500}^o}C,lln }}{C_2}{H_2} + 3{H_2}\) \({C_2}{H_2} + HCl\xrightarrow{{}}C{H_2} = CHCl\) \(nC{H_2} = CHCl\xrightarrow{{{t^o},xt}}{( – C{H_2} – CHCl – )_n}\) (P.V.C) Bình luận
CH3COONA -> CH4 -> C2H2 -> CH2=CH-Cl -> PVC 1,$CH_3COONa + NaOH \xrightarrow[]{CaO,t^o} CH_4 + Na_2CO3$ 2,$2CH_4 \xrightarrow[]{1500t^o,LLN} C_2H_2 + 3H_2$ 3,$CH≡CH$ + $HCl$ ${\rightarrow}$ $CH_2=CH-Cl$ 4,$nCH_2=CH-Cl$ $\xrightarrow[p]{t^o,xt}$$(\kern-6pt- CH_2-CH -\kern-6pt)_n$ | $Cl$ Bình luận
Các phản ứng xảy ra:
\(C{H_3}COONa + NaOH\xrightarrow{{CaO,{t^o}}}C{H_4} + N{a_2}C{O_3}\)
\(2C{H_4}\xrightarrow{{{{1500}^o}C,lln }}{C_2}{H_2} + 3{H_2}\)
\({C_2}{H_2} + HCl\xrightarrow{{}}C{H_2} = CHCl\)
\(nC{H_2} = CHCl\xrightarrow{{{t^o},xt}}{( – C{H_2} – CHCl – )_n}\) (P.V.C)
CH3COONA -> CH4 -> C2H2 -> CH2=CH-Cl -> PVC
1,$CH_3COONa + NaOH \xrightarrow[]{CaO,t^o} CH_4 + Na_2CO3$
2,$2CH_4 \xrightarrow[]{1500t^o,LLN} C_2H_2 + 3H_2$
3,$CH≡CH$ + $HCl$ ${\rightarrow}$ $CH_2=CH-Cl$
4,$nCH_2=CH-Cl$ $\xrightarrow[p]{t^o,xt}$$(\kern-6pt- CH_2-CH -\kern-6pt)_n$
|
$Cl$