Toán Làm phép chia: `a,(x^5+4x^3-6x^2):4x^2` `b, (x^3-8):(x^2+2x+4)` 02/12/2021 By Rylee Làm phép chia: `a,(x^5+4x^3-6x^2):4x^2` `b, (x^3-8):(x^2+2x+4)`
Đáp án: a, `(x^5+4x^3-6x^2):4x^2` `=x^2(x^3+4x-6):4x^2` `=(x^3+4x-6):4` `=(x^3+4x-6)/4` b, `(x^3-8):(x^2+2x+4)` `=(x-2)(x^2+2x+4):(x^2+2x+4)` `=x-2` Trả lời
`~rai~` $\begin{array}{I} a) (x^5+4x^3-6x^2):4x^2\\=\dfrac{x^3}{4}+x-\dfrac{3}{2}.\\b) (x^3-8):(x^2+2x+4)\\=(x-2)(x^2+2x+4):(x^2+2x+4)=x-2.\end{array}$ Trả lời
Đáp án:
a,
`(x^5+4x^3-6x^2):4x^2`
`=x^2(x^3+4x-6):4x^2`
`=(x^3+4x-6):4`
`=(x^3+4x-6)/4`
b,
`(x^3-8):(x^2+2x+4)`
`=(x-2)(x^2+2x+4):(x^2+2x+4)`
`=x-2`
`~rai~`
$\begin{array}{I} a) (x^5+4x^3-6x^2):4x^2\\=\dfrac{x^3}{4}+x-\dfrac{3}{2}.\\b) (x^3-8):(x^2+2x+4)\\=(x-2)(x^2+2x+4):(x^2+2x+4)=x-2.\end{array}$