Lm nhanh giúp em ạ , ai lm nhanh em vote 5 sao ạ a) |4x+1| = 1/2 b) |4x+2|=0 c)|1/2x-3|=2/3 d)(x-3)^2=1/4

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1. Đáp án:

   a, Ta có : 

   $| 4x + 1| = 1/2$

   <=>  \(\left[ \begin{array}{l}4x + 1 = 1/2\\4x + 1 = -1/2\end{array} \right.\) 

   <=> \(\left[ \begin{array}{l}x = -1/8\\x=-3/8\end{array} \right.\) 

   b, Ta có : 

   $|4x + 2| = 0$

   $ <=> 4x + 2 = 0$

   $ <=> x = -1/2$

   c, Ta có : 

   $|1/2x – 3| = 2/3$

   <=> \(\left[ \begin{array}{l}1/2x – 3 = 2/3\\1/2x – 3 = -2/3\end{array} \right.\) 

   <=> \(\left[ \begin{array}{l}x=22/3\\x=14/3\end{array} \right.\) 

   d, Ta có : 

   $( x – 3)^2 = 1/4$

   <=> \(\left[ \begin{array}{l}x – 3 = 1/2\\x – 3 = -1/2\end{array} \right.\) 

   <=> \(\left[ \begin{array}{l}x=7/2\\x=5/2\end{array} \right.\) 

   Giải thích các bước giải:

    

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2. Giải thích các bước giải:

    a) `|4x+1|=1/2`

   `=>`\(\left[ \begin{array}{l}4x+1=\dfrac12\\4x+1=-\dfrac12\end{array} \right.\) `=>`\(\left[ \begin{array}{l}4x=-\dfrac12\\4x=-\dfrac32\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=-\dfrac18\\x=-\dfrac38\end{array} \right.\)

    b) `|4x+2|=0`

   `=>4x+2=0`

   `=>4x=-2`

   `=>x=-1/2`

    c) `|1/2x-3|=2/3`

   `=>`\(\left[ \begin{array}{l}\dfrac12x-3=\dfrac23\\\dfrac12x-3=-\dfrac23\end{array} \right.\) `=>`\(\left[ \begin{array}{l}\dfrac12x=-\dfrac{11}3\\\dfrac12x=\dfrac73\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=-\dfrac{22}3\\x=-\dfrac{14}3\end{array} \right.\)

    d) `(x-3)^2=1/4`

   `=>`\(\left[ \begin{array}{l}x-3=\dfrac12\\x-3=-\dfrac12\end{array} \right.\) `=>`\(\left[ \begin{array}{l}x=\dfrac72\\x=\dfrac52\end{array} \right.\)

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