m/ |x+3| = 4 n/ [x-1] = 5 o/ |7+x| = 9 p/ 2|x-3|=8 q/ |x+5| = 0 03/07/2021 Bởi Parker m/ |x+3| = 4 n/ [x-1] = 5 o/ |7+x| = 9 p/ 2|x-3|=8 q/ |x+5| = 0
m, |x+3|=4 ⇒\(\left[ \begin{array}{l}x+3=4\\x+3=-4\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=1\\x=-7\end{array} \right.\) n, |x-1|=5 ⇒\(\left[ \begin{array}{l}x-1=5\\x-1=-5\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=6\\x=-4\end{array} \right.\) p, 2|x-3|=8 ⇒|x-3|=4 ⇒\(\left[ \begin{array}{l}x-3=4\\x-3=-4\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=7\\x=-1\end{array} \right.\) q, |x+5|=0 ⇒x+5=0 ⇒x=-5 Chúc bạn học tốt nhé! ^^ Bình luận
Giải thích các bước giải: m,C1:|x+3|=4 n,C1[x-1]=5 o,C1:|7+x| p,C1:2|x-3|=8 q,|x+5|=0 x-3=4 x-1=5 7+x=9 |x-3|=4 x+5=0 x=7 x=6 x=2 x-3=4 x=-5 m,C2:x-3=-4 n,C2:x-1=-5 o,C2:7+x=-9 x=7 x=-1 x=-4 x=-16 p,C2:x-3=-4 x=-1 Bình luận
m, |x+3|=4
⇒\(\left[ \begin{array}{l}x+3=4\\x+3=-4\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=1\\x=-7\end{array} \right.\)
n, |x-1|=5
⇒\(\left[ \begin{array}{l}x-1=5\\x-1=-5\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=6\\x=-4\end{array} \right.\)
p, 2|x-3|=8
⇒|x-3|=4
⇒\(\left[ \begin{array}{l}x-3=4\\x-3=-4\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=7\\x=-1\end{array} \right.\)
q, |x+5|=0
⇒x+5=0
⇒x=-5
Chúc bạn học tốt nhé! ^^
Giải thích các bước giải:
m,C1:|x+3|=4 n,C1[x-1]=5 o,C1:|7+x| p,C1:2|x-3|=8 q,|x+5|=0
x-3=4 x-1=5 7+x=9 |x-3|=4 x+5=0
x=7 x=6 x=2 x-3=4 x=-5
m,C2:x-3=-4 n,C2:x-1=-5 o,C2:7+x=-9 x=7
x=-1 x=-4 x=-16 p,C2:x-3=-4
x=-1