Mn giúp mk tìm nghiệm pt Căn 4-x bình nhân sin2x=0 01/10/2021 Bởi Ivy Mn giúp mk tìm nghiệm pt Căn 4-x bình nhân sin2x=0
$\begin{array}{l} \sqrt {4 – {x^2}} \sin 2x = 0\,\,\,\left( * \right)\\ DK:\,\,\,4 – {x^2} \ge 0 \Leftrightarrow – 2 \le x \le 2\\ \left( * \right) \Leftrightarrow \left[ \begin{array}{l} \sqrt {4 – {x^2}} = 0\\ \sin 2x = 0 \end{array} \right. \Leftrightarrow \left[ \begin{array}{l} {x^2} – 4 = 0\\ 2x = k\pi \,\,\, \end{array} \right.\\ \Leftrightarrow \left[ \begin{array}{l} x = \pm 2\\ x = \frac{{k\pi }}{2}\,\,\left( {k \in Z} \right) \end{array} \right.\\ – 2 \le x \le 2 \Rightarrow – 2 \le \frac{{k\pi }}{2} \le 2 \Leftrightarrow – 1,27 \le k \le 1,27\\ \Rightarrow k = 0 \Rightarrow x = 0\\ Vay\,\,pt\,\,co\,\,tap\,\,nghiem:\,\,\,S = \left\{ { – 2;\,\,0;\,\,2} \right\}. \end{array}$ Bình luận
$\begin{array}{l}
\sqrt {4 – {x^2}} \sin 2x = 0\,\,\,\left( * \right)\\
DK:\,\,\,4 – {x^2} \ge 0 \Leftrightarrow – 2 \le x \le 2\\
\left( * \right) \Leftrightarrow \left[ \begin{array}{l}
\sqrt {4 – {x^2}} = 0\\
\sin 2x = 0
\end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
{x^2} – 4 = 0\\
2x = k\pi \,\,\,
\end{array} \right.\\
\Leftrightarrow \left[ \begin{array}{l}
x = \pm 2\\
x = \frac{{k\pi }}{2}\,\,\left( {k \in Z} \right)
\end{array} \right.\\
– 2 \le x \le 2 \Rightarrow – 2 \le \frac{{k\pi }}{2} \le 2 \Leftrightarrow – 1,27 \le k \le 1,27\\
\Rightarrow k = 0 \Rightarrow x = 0\\
Vay\,\,pt\,\,co\,\,tap\,\,nghiem:\,\,\,S = \left\{ { – 2;\,\,0;\,\,2} \right\}.
\end{array}$