P(x)=5x^3-3x+7-x;Q(x)=-5x^3+2x-3+2x-x^2 M(x)=P(x)+Q(x).tính M(x) 10/08/2021 Bởi Jasmine P(x)=5x^3-3x+7-x;Q(x)=-5x^3+2x-3+2x-x^2 M(x)=P(x)+Q(x).tính M(x)
Đáp án: $\rm \\P(x)=5x^3-3x+7-x\\=5x^3-4x+7\\Q(x)=-5x^3+2x-3+2x-x^2\\=-5x^3-x^2+4x-3\\P(x)+Q(x)\\=5x^3-4x+7-5x^3-x^2+4x-3\\=-x^2+4$ Bình luận
Gửi lại nha! Cho mk xin ctlhhn nha
Đáp án:
$\rm \\P(x)=5x^3-3x+7-x\\=5x^3-4x+7\\Q(x)=-5x^3+2x-3+2x-x^2\\=-5x^3-x^2+4x-3\\P(x)+Q(x)\\=5x^3-4x+7-5x^3-x^2+4x-3\\=-x^2+4$