Phân tích ra hộ em ạ Tanx=-√3-2 Tanx=-√3+2 30/09/2021 Bởi Lyla Phân tích ra hộ em ạ Tanx=-√3-2 Tanx=-√3+2
\[\begin{array}{l} \tan x = – \sqrt 3 – 2\,\,\,\left( {\cos x \ne 0} \right)\\ \Leftrightarrow \tan x = \tan \left( { – \frac{{5\pi }}{{12}}} \right)\\ \Leftrightarrow x = – \frac{{5\pi }}{{12}} + k\pi \,\,\left( {k \in Z} \right)\\ \tan x = – \sqrt 3 + 2\,\,\,\left( {\cos x \ne 0} \right)\\ \Leftrightarrow \tan x = \tan \frac{\pi }{{12}}\\ \Leftrightarrow x = \frac{\pi }{{12}} + k\pi \,\,\left( {k \in Z} \right) \end{array}\] Bình luận
\[\begin{array}{l}
\tan x = – \sqrt 3 – 2\,\,\,\left( {\cos x \ne 0} \right)\\
\Leftrightarrow \tan x = \tan \left( { – \frac{{5\pi }}{{12}}} \right)\\
\Leftrightarrow x = – \frac{{5\pi }}{{12}} + k\pi \,\,\left( {k \in Z} \right)\\
\tan x = – \sqrt 3 + 2\,\,\,\left( {\cos x \ne 0} \right)\\
\Leftrightarrow \tan x = \tan \frac{\pi }{{12}}\\
\Leftrightarrow x = \frac{\pi }{{12}} + k\pi \,\,\left( {k \in Z} \right)
\end{array}\]