phân tích thành nhân tử : a, x-1+x^2-2x+1 24/10/2021 Bởi Bella phân tích thành nhân tử : a, x-1+x^2-2x+1 b, x^3-2x^2+x c, 12x^2y -18xy^2-30y^2 d, 5(x-y)-y(x-y) e, 11x +11y-x^2-xy
`a,x-1+x^2-2x+1` `=(x-1)+(x-1)^2` `=(x-1)(1+x-1)` `=x(x-1)` `b,x^3-2x^2+x` `=x(x^2-2x+1)` `=x(x-1)^2` `c,12x^2y-18xy^2-30y^2` `=6y(2x^2-3xy-5y)` `d,5(x-y)-y(x-y)` `=(5-y)(x-y)` `e,11x+11y-x^2-xy` `=11(x+y)-x(x+y)` `=(11-x)(x+y)` Bình luận
a) ${ x-1+x^2-2x+1}$ ${ = (x^2-2x+1)+(x-1)}$ ${ = (x-1)^2+(x-1)}$ ${ = (x-1).(x-1+1)}$ ${ = x.(x-1)}$ b) ${ x^3-2x^2+x }$ ${ = x.(x^2-2x+1)}$ ${= x.(x-1)^2}$ c) ${12x^2y -18xy^2-30y^2}$ ${= 6.(2x^2y-3xy^2-10y^2)}$ d) ${ 5(x-y)-y(x-y) }$ ${ = (5-y).(x-y)}$ e) ${ 11x +11y-x^2-xy}$ ${ = 11.(x+y)-x.(x+y)}$ ${ = (11-x).(x+y)}$ Bình luận
`a,x-1+x^2-2x+1`
`=(x-1)+(x-1)^2`
`=(x-1)(1+x-1)`
`=x(x-1)`
`b,x^3-2x^2+x`
`=x(x^2-2x+1)`
`=x(x-1)^2`
`c,12x^2y-18xy^2-30y^2`
`=6y(2x^2-3xy-5y)`
`d,5(x-y)-y(x-y)`
`=(5-y)(x-y)`
`e,11x+11y-x^2-xy`
`=11(x+y)-x(x+y)`
`=(11-x)(x+y)`
a) ${ x-1+x^2-2x+1}$
${ = (x^2-2x+1)+(x-1)}$
${ = (x-1)^2+(x-1)}$
${ = (x-1).(x-1+1)}$
${ = x.(x-1)}$
b) ${ x^3-2x^2+x }$
${ = x.(x^2-2x+1)}$
${= x.(x-1)^2}$
c) ${12x^2y -18xy^2-30y^2}$
${= 6.(2x^2y-3xy^2-10y^2)}$
d) ${ 5(x-y)-y(x-y) }$
${ = (5-y).(x-y)}$
e) ${ 11x +11y-x^2-xy}$
${ = 11.(x+y)-x.(x+y)}$
${ = (11-x).(x+y)}$