PTĐT THÀNH NHÂN TỬ 8, 3.(x-y) – 5x.(y-x) 9, x.(y-1) + y.(1-y) 10, x^3 – 2x^2 +x 11, 2x^2 + 4x + 2 – 2y^2 12, 2x – 2y – x^2 + 2xy – y^2 13, x^3 + 2x^2

PTĐT THÀNH NHÂN TỬ
8, 3.(x-y) – 5x.(y-x)
9, x.(y-1) + y.(1-y)
10, x^3 – 2x^2 +x
11, 2x^2 + 4x + 2 – 2y^2
12, 2x – 2y – x^2 + 2xy – y^2
13, x^3 + 2x^2y + xy^2 – 9x

0 bình luận về “PTĐT THÀNH NHÂN TỬ 8, 3.(x-y) – 5x.(y-x) 9, x.(y-1) + y.(1-y) 10, x^3 – 2x^2 +x 11, 2x^2 + 4x + 2 – 2y^2 12, 2x – 2y – x^2 + 2xy – y^2 13, x^3 + 2x^2”

  1. 8/

    `3(x-y)-5x(y-x)`

    `⇔3(x-y)+5x(x-y)`

    `⇔(3+5x)(x-y)`

    9/

    `x(y-1)+y(1-y)`

    `⇔x(y-1)-y(1-y)`

    `⇔(x-y)(1-y)`

    10/

    `x^3-2x^2+x`

    `⇔x^3-x^2-x^2+x`

    `⇔x^2(x-1)-x(x-1)`

    `⇔(x^2-x)(x-1)`

    `⇔x(x-1)^2`

    11/

    `2x^2+4x+2-2y^2`

    `⇔2(x^2+2x+1-y^2)`

    `⇔2[(x+1)^2-y^2]`

    `⇔2(x+1-y)(x+1+y)`

    12/

    `2x-2y-x^2+2xy-y^2`

    `⇔-(x^2-2xy+y^2-2x+2y)`

    `⇔-[(x-y)^2-2(x-y)]`

    `⇔-(x-y)(x-y-2)`

    13/

    `x^3+2x^2y+xy^2-9x`

    `⇔x(x^2+2xy+y^2-9)`

    `⇔x[(x+y)^2-3^2]`

    `⇔x(x+y-3)(x+y+3)`

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  2. Đáp án:

     8) 3(x-y)+5x (x-y)

    ⇔ (3+5x)(x-y)

    9) x(y-1)+y(1-y)

    ⇔ x(y-1)-y(y-1)

    ⇔ (x-y)(y-1)

    10) x³-2x²+x

    ⇔ x(x²-2x+1)

    ⇔ x(x-1)²

    11) 2x²+4x+2-2y²

    ⇔ 2(x²+2x+1-y²)

    ⇔ 2((x+1)²-y²)

    ⇔ 2(x+1-y).(x+1+y)

    12) 2x-2y-x²+2xy-y²

    13) x³+2x²2y+xy²-9x

    ⇔ x³+4x²y+xy²-9x

    ⇔ x(x²+4xy+y²-9)

    Giải thích các bước giải: hì câu 12 ko bt lm

     

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