PTĐTTN theo dạng đối xứng vòng quanh 1.(a-b)(b-c)(a-c)+(a+b)(b+c)(a-c)+(a+b)(a+c)(c-b) NHANH MIK VOTE 5 SAO

Đáp án:

Giải thích các bước giải:

(b+c)(c+a)(b−a)+(b+c)(a+b)(a−c)+(a−b)(b−c)(a−c)(b+c)(c+a)(b−a)+(b+c)(a+b)(a−c)+(a−b)(b−c)(a−c)

=(b+c)(c+a)(b−a)+(b+c)(a+b)(a−b+b−c)+(a−b)(b−c)(a−c)=(b+c)(c+a)(b−a)+(b+c)(a+b)(a−b+b−c)+(a−b)(b−c)(a−c)

=(b+c)(c+a)(b−a)+(b+c)(a+b)(a−b)+(b+c)(a+b)(b−c)+(a−b)(b−c)(a−c)=(b+c)(c+a)(b−a)+(b+c)(a+b)(a−b)+(b+c)(a+b)(b−c)+(a−b)(b−c)(a−c)

=(b+c)(a−b)(a+b−c−a)+(b−c)[(b+c)(a+b)+(a−b)(a−c)]=(b+c)(a−b)(a+b−c−a)+(b−c)[(b+c)(a+b)+(a−b)(a−c)]

=(b+c)(a−b)(b−c)+(b−c)[(b+c)(a+b)+(a−b)(a−c)]=(b+c)(a−b)(b−c)+(b−c)[(b+c)(a+b)+(a−b)(a−c)]

=(b−c)[(b+c)(a−b)+(b+c)(a+b)+(a−b)(a−c)]=(b−c)[(b+c)(a−b)+(b+c)(a+b)+(a−b)(a−c)]

=(b−c)[(b+c)(a−b+a+b)+(a−b)(a−c)]=(b−c)[(b+c)(a−b+a+b)+(a−b)(a−c)]

=(b−c)[(b+c).2a+(a−b)(a−c)]=(b−c)[(b+c).2a+(a−b)(a−c)]

=(b−c)(2ab+2ac+a2−ab−ca+bc)=(b−c)(2ab+2ac+a2−ab−ca+bc)

=(b−c)(a2+ab+ac+bc)=(b−c)(a2+ab+ac+bc)

=(b−c)[a(a+b)+c(a+b)]=(b−c)[a(a+b)+c(a+b)]

=(b−c)(a+b)(a+c)