Toán (2x+3).(3-2x)-(2x-1)^2=? Giải giúp mik vs -_- 12/09/2021 By Aaliyah (2x+3).(3-2x)-(2x-1)^2=? Giải giúp mik vs -_-
Đáp án: $\begin{array}{l} \left( {2x + 3} \right)\left( {3 – 2x} \right) – {\left( {2x – 1} \right)^2}\\ = – \left( {2x + 3} \right)\left( {2x – 3} \right) – \left( {4{x^2} – 4x + 1} \right)\\ = – \left( {4{x^2} – 9} \right) – 4{x^2} + 4x – 1\\ = – 4{x^2} + 9 – 4{x^2} + 4x – 1\\ = 4x + 8 \end{array}$ Trả lời
Đáp án:
$\begin{array}{l}
\left( {2x + 3} \right)\left( {3 – 2x} \right) – {\left( {2x – 1} \right)^2}\\
= – \left( {2x + 3} \right)\left( {2x – 3} \right) – \left( {4{x^2} – 4x + 1} \right)\\
= – \left( {4{x^2} – 9} \right) – 4{x^2} + 4x – 1\\
= – 4{x^2} + 9 – 4{x^2} + 4x – 1\\
= 4x + 8
\end{array}$